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Suppose that you are standing on a train accelerating at 0.23g What minimum coefficient of static friction must exist between your feet and the floor if you are not to slide?
Dkidder1
Assuming body mass of m, your weight would be Q = mg.
Force due to that much acceleration would be
F = 34100mg,
and it would have to be completely countered by force of friction:
T = fQ = fmg.
Comparing the two equations:
f = 34100 which is an astronomical number and no combination of surface materials can ever achieve that.
Assumed acceleration of 34100 G is ridiculous at best, not even bolting the body to surface would hold it - assuming body mass of 100 kg, the experienced force of inertia would be in order of 3 500 000 kG.
Wiki User
∙ 15y ago
Wiki User
∙ 9y agoUnfortunately 0.40g is not a unit of acceleration, but a unit of mass. Units of acceleration should be in meters per second (m/s).
Wiki User
∙ 13y ago0.23
Nathan Estifanos
Wiki User
∙ 10y ago.14
Nathan Estifanos
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