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The formula for percent work efficiency is:

percent efficiency = (work output/work input) x 100

To find the answer to this question, you just need to plug the given values into the formula. The problem tells you that the work input is 240 J and the percent efficiency is 75 %, so

75 = (work output/240) x 100

Now, solve for work output:

-first divide by 100

.75 = (work output/240)

-then multiply by 240

180 J = work output (in units of joules because work is measured in joules)

And there's your answer. Hope this helped!

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The efficiency of a ramp is 75. If the amount of work input is 240 J what is the amount of useful work output?

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