The formula for percent work efficiency is:
percent efficiency = (work output/work input) x 100
To find the answer to this question, you just need to plug the given values into the formula. The problem tells you that the work input is 240 J and the percent efficiency is 75 %, so
75 = (work output/240) x 100
Now, solve for work output:
-first divide by 100
.75 = (work output/240)
-then multiply by 240
180 J = work output (in units of joules because work is measured in joules)
And there's your answer. Hope this helped!
That may refer to the system's efficiency (which is formally the amount of useful output power divided by the amount of input power).
The efficiency of a machine is found by dividing the amount of work done by a machine by the amount of energy used by a machine. The answer is then multiplied by 100 to give a percentage.
Efficiency
Efficiency = useful output power / input power
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That may refer to the system's efficiency (which is formally the amount of useful output power divided by the amount of input power).
That may refer to the system's efficiency (which is formally the amount of useful output power divided by the amount of input power).
The efficiency of a machine is found by dividing the amount of work done by a machine by the amount of energy used by a machine. The answer is then multiplied by 100 to give a percentage.
Efficiency = useful output power / input power
Efficiency
Efficiency = useful output power / input power
The relationship between input work and useful output work can be represented by efficiency. Efficiency is the ratio of useful output work to input work. A higher efficiency indicates that a larger proportion of the input work is converted into useful output work, while a lower efficiency suggests that more of the input work is wasted or converted into non-useful forms.
The efficiency is output divided by input.
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That is called the efficiency, and it is a number between 0 and 1 (or 0% and 100%). It is obtained by dividing output power / input power.
You divide useful output energy by the input energy. Or equivalently, useful output power by input power.
Efficiency