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What is the frequency and energy of a photon with a wavelength of 488.3 nm?
The frequency of a photon with a wavelength of 488.3 nm is approximately 6.15 x 10^14 Hz. The energy of this photon is approximately 2.54 eV.
What is the energy of a 500 nm photon?
The energy of a 500 nm photon is 3.1 eV (electron volts). This is a unit of measure used to represent the energy of a single photon. To put this into perspective, a single photon of visible light has an energy of 1.8 to 3.1 eV, and a single photon of ultraviolet light has an energy of 3.1 to 124 eV. The energy of a 500 nm photon can be calculated by using the following equation: E = hc/ Where: E = energy of the photon (in eV) h = Planck's constant (6.626 * 10-34 Js) c = speed of light (2.998 * 108 m/s) = wavelength of photon (in meters) Therefore, the energy of a 500 nm photon is calculated as follows: Convert the wavelength from nanometers to meters: 500 nm = 0.0005 m Insert the values into the equation: E = (6.626 * 10-34 Js) * (2.998 * 108 m/s) / (0.0005 m) Calculate the energy: E = 3.1 eVTherefore, the energy of a 500 nm photon is 3.1 eV.
What is the energy of a 170 nm ultraviolet photon?
The energy of a photon can be calculated using the formula E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon. Plugging in the values for a 170 nm ultraviolet photon gives an energy of approximately 7.3 eV.
What is the wavelength of a photon whose energy is twice that of a photon with a 580 nm wavelength?
Since the energy of a photon is inversely proportional to its wavelength, for a photon with double the energy of a 580 nm photon, its wavelength would be half that of the 580 nm photon. Therefore, the wavelength of the photon with twice the energy would be 290 nm.
What is the energy of a photon emitted with a wavelength of 518 mp?
The energy of a photon can be calculated using the equation E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength. Plugging in the values, the energy of a photon with a wavelength of 518 nm is approximately 3.82 eV.
What is the frequency and energy of a photon with a wavelength of 488.3 nm?
The frequency of a photon with a wavelength of 488.3 nm is approximately 6.15 x 10^14 Hz. The energy of this photon is approximately 2.54 eV.
What is the energy of a 500 nm photon?
The energy of a 500 nm photon is 3.1 eV (electron volts). This is a unit of measure used to represent the energy of a single photon. To put this into perspective, a single photon of visible light has an energy of 1.8 to 3.1 eV, and a single photon of ultraviolet light has an energy of 3.1 to 124 eV. The energy of a 500 nm photon can be calculated by using the following equation: E = hc/ Where: E = energy of the photon (in eV) h = Planck's constant (6.626 * 10-34 Js) c = speed of light (2.998 * 108 m/s) = wavelength of photon (in meters) Therefore, the energy of a 500 nm photon is calculated as follows: Convert the wavelength from nanometers to meters: 500 nm = 0.0005 m Insert the values into the equation: E = (6.626 * 10-34 Js) * (2.998 * 108 m/s) / (0.0005 m) Calculate the energy: E = 3.1 eVTherefore, the energy of a 500 nm photon is 3.1 eV.
What is the energy of a 170 nm ultraviolet photon?
The energy of a photon can be calculated using the formula E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon. Plugging in the values for a 170 nm ultraviolet photon gives an energy of approximately 7.3 eV.
What is the wavelength of a photon whose energy is twice that of a photon with a 580 nm wavelength?
Since the energy of a photon is inversely proportional to its wavelength, for a photon with double the energy of a 580 nm photon, its wavelength would be half that of the 580 nm photon. Therefore, the wavelength of the photon with twice the energy would be 290 nm.
Transition A produces light with a wavelength of 400 nm Transition B involves twice as much energy as A What wavelenth light does it produce?
Transition B produces light with half the wavelength of Transition A, so the wavelength is 200 nm. This is due to the inverse relationship between energy and wavelength in the electromagnetic spectrum.
What is the energy of a photon emitted with a wavelength of 518 mp?
The energy of a photon can be calculated using the equation E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength. Plugging in the values, the energy of a photon with a wavelength of 518 nm is approximately 3.82 eV.
What is the energy of a photon emitted with a wave length of 654 nm?
The energy of a photon can be calculated using the equation E = hc/λ, where E is the energy of the photon, h is Planck's constant (6.626 x 10^-34 J*s), c is the speed of light (3.0 x 10^8 m/s), and λ is the wavelength of the photon. Plugging in the values, the energy of a photon emitted with a wavelength of 654 nm (or 6.54 x 10^-7 m) is approximately 3.02 x 10^-19 J.
What is the energy of a photon with a wavelength of 500 nm in kilo electron volts (keV)?
The energy of a photon with a wavelength of 500 nm is approximately 2.48 keV.
What is the energy in eV of the red light?
About 1.9 eV. Duane-Hunt relation is E(eV) = 1240/lambda(nm), lambda for red light is 650 nm, so E in eV is about 1.9
When hydrogen electrons goes from n equals 3 to n equals 1 what happens?
When an electron goes from a higher state to a lower state, it gives up energy equal to the difference of energy levels of the two states. This energy is in the form of a photon. If it goes directly from n=3 to n=1, then 1 photon is emitted. If it transitions from n=3 to n=2, then from n=2 to n=1, two (2) photons are emitted. Energy level of n=3 for Hydrogen is -1.511 eV (electron volts) Energy level of n=2 for Hydrogen is -3.4 eV (electron volts) Energy level of n=3 for Hydrogen is -13.6 eV (electron volts) The energy levels are 'more negative' at lower levels because the electron becomes more bound to the atom. From n=3 to 1 (gives up 12.089 eV, or a photon with wavelength 102.518 nm - ultraviolet light) From n=3 to 2 (gives up 1.889 eV, or a photon with wavelength 656.112 nm - red light) From n=2 to 1 (gives up 10.2 eV, or a photon with wavelength 121.5 nm - ultraviolet) See related link post.
What is the photon energy of red light having wavelength 640 nm?
The photon energy of red light with a wavelength of 640 nm is approximately 1.94 eV (electron volts). This can be calculated using the formula E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength of the light.
What is the energy in electric volts of a 200 nano meter ultraviolet photon?
The energy of a photon is calculated using the formula E = hc/λ, where h is Planck's constant (6.63 x 10^-34 Js), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength of the photon (200 nm = 200 x 10^-9 m). Plugging in the values gives E = (6.63 x 10^-34 Js * 3 x 10^8 m/s) / 200 x 10^-9 m = 9.945 x 10^-19 Joules. To convert this to electron volts (eV), divide by the elementary charge e = 1.6 x 10^-19 C to get 0.622 eV.
