parallel to the surface of the Earth
Tangential velocity is equal to (mass x velocity^2)/radial distance
Vt=w*r where; * is multiply Vt is tangential velocity w is omega(angular mometum) r is radius
Yes. Imagine a ball on a rigid pole being swung around, and slowing down. It's tangential velocity is positive but it's tangential acceleration is negative
Because there is no tangential force acting on the object in uniform circular motion. The proof that there is no tangential component of acceleration is the fact that the tangential component of velocity is constant.
A satellite is in free fall. When the only force acting upon it is gravity, it reacts freely to this gravity, accelerating towards Earth. That is to say, instead of going in a straight line, the velocity vector changes direction, towards Earth. If the satellite is fast enough to be in orbit, it will never actually fall on Earth; but the velocity vector changes all the time.
velocity of any satellite revolving around any planet is 0 with reference to cos theta. the velocity in circular motion is taken in tangential direction. when the velocity of any satellite is taken tangential , then it forms 90 degrees with the radius of the Earth. we know that cos90 = 0. therefore,velocity of satellites is 0 with reference to cos theta. but this contradicts the fact that " any body with 0 velocity would collide the Earth" stated by Issac Newton. scientists are still researching to get an appropriate answer to this question. - by d.s.rahul
If the path is perfectly circular, yes, the speed is constant. This should not be confused with the velocity, because while speed is constant, its direction is not; therefore velocity is always changing.
Tangential velocity is equal to (mass x velocity^2)/radial distance
The Moons tangential velocity is constantly changing in direction as it falls around the Earth.
Tangential velocity squared is GMs/r and velocity v =29814m/s and the centripetal acceleration is v2/r= 5.928 E-3 m/s2
They're given enough tangential velocity ('sideways' speed, parallel to the earth's surface) so that the curve of the earth falls away just as fast as the satellite falls.
WikiAnswers cannot support diagrams - sorry. A satellite around the Earth will have an elliptical or (in some cases) a circular orbit. The satellite is constantly accelerating towards the Earth due to the gravity between the Earth and the satellite. However, because of the satellite's tangential velocity, it stays at a relatively constant distance from the Earth.
Vt=w*r where; * is multiply Vt is tangential velocity w is omega(angular mometum) r is radius
Yes. Imagine a ball on a rigid pole being swung around, and slowing down. It's tangential velocity is positive but it's tangential acceleration is negative
the tangential velocity is equal to the angular velocity multiplied by the radius the tangential velocity is equal to the angular velocity multiplied by the radius
The Earth's rotation
in my opinion, the velocity of any body moving in a circular path is directed in tangential direction. when the velocity is took tangential,its angle formed with reference to the earths radius is 90 degrees. we know that cos90 = 0. therefore,the velocity of the satellites revolving around the earth must be 0 with reference to cos theta. velocity of any satellite revolving around any planet is 0 with reference to cos theta. but this contradicts the fact that " any body with 0 velocity would collide the Earth" stated by Issac Newton. scientists are still researching to get an appropriate answer to this question. - by d.s.rahul