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I assume you mean 30o Celsius. Use this formula.

q(joules) = mass * specific heat * change in temperature

q = (15 grams water)(4.180 J/gC)(40o C - 30o C)

= 627 joules

==========( perhaps 630 joules to be in significant figures territory )

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Q: The temperature of 15 grams of water is increased by 3.0 Celsius degrees How much heat in Joules was absorbed by the water?
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