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Answer #1:

Reading between the lines, this has to be the electrostatic force.

Two "small masses" at that distance couldn't possibly attract each other with

that much force due to gravitation.

The other two forces (the weak and strong nuclear forces) have ranges that

are much much less than that.

If you wanted the number rather than the name of the force, then you just

need to look up Coulomb's Law and find how it varies by distance (the r squared

term should be a clue here). Halving the distance multiplies the force by 4.

================================

Observation:

Answer #1 is correct, and stunningly perspicacious as well.

If the centers of these masses are 10m apart and the gravitational force

between them is 10 N, then the product of the masses is 1.5 x 1013 kg2. (rounded)

You've said that they can be moved to where their centers are 5m apart.

So if, say, they are spheres, then their radii can't sum to more than 5m.

Let's say that they are two spheres with equal size and equal mass. Then for

each one, the radius is 2.5m, the volume is 65.45 m3, the mass is 3.87 x 106 kg,

and the density is 59,175 gm/cm3 .

Just now, I have nothing to compare that density to, so I'm not sure whether

you have a pair of baby black holes there, or simply a few cupfulls of plain old

nuclear fluid or Sirius-B.

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10y ago
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12y ago

-- You remember when the class was learning that the mutual forces of gravity

are inversely proportional to the square of the distance between the masses.

-- You scratch your head wondering what the heck that means.

-- You take it to a friend who was awake and listening that day, and he explains how

it means that when you cut the distance in half, the force becomes 4 times stronger.

-- As soon as you hear that, you realize how easy the problem is, and you whip out

the answer with no trouble at all.

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13y ago

40.0 N

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Q: Two small masses that are 10 cm apart attract each other with a force of 10 N when they are 5 cm apart these masses will attract each other with what force?
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