0
What else can I help you with?
What is the relationship between the electric field intensity (E), charge density (q), and permittivity of free space ()?
The relationship between the electric field intensity (E), charge density (q), and permittivity of free space () is given by the equation E q / (). This equation shows that the electric field intensity is directly proportional to the charge density and inversely proportional to the permittivity of free space.
What is the relationship between the electric field (E), permittivity of free space (), and electric charge density () in a given system?
The relationship between the electric field (E), permittivity of free space (), and electric charge density () in a given system is described by Gauss's Law, which states that the electric field (E) at a point in space is directly proportional to the electric charge density () at that point and inversely proportional to the permittivity of free space (). Mathematically, this relationship is represented as E / .
What is the formula for calculating the electric flux through a surface due to a point charge, taking into account the permittivity of free space, represented by the symbol epsilon naught?
The formula for calculating the electric flux through a surface due to a point charge is given by q / , where is the electric flux, q is the charge, and is the permittivity of free space.
What is dimension of permittivity of vacumm?
The dimension of permittivity of vacuum, also known as vacuum permittivity or electric constant, is F/m (coulomb per volt per meter). It is denoted by ε₀ and has a value of approximately 8.854 x 10^-12 F/m.
What is difference between absolute permittivity and relative permittivity of medium?
The absolute permittivity of a medium is its relative permittivity multiplied by the vacuum permittivity. The absolute permittivity is a proportionality constant between the electric and displacement field with units of Farad/meters (in SI units). This number is usually very small (e.g. for air: 0.000 000 000 008 85 F/m). The relative permittivity is a unit-less number scaled upward to present nicer numbers (e.g. for air: 1.0005). To get the absolute permittivity from the relative permittivity one should multiply with the vacuum permittivity: 8.85418781... E-12 F/m.
Why dielectric constant has no units?
The dielectric constant, also known as relative permittivity, is a dimensionless quantity that represents the ratio of a material's permittivity to the permittivity of free space (vacuum). Since it is defined as a ratio of two similar quantities (both having units of capacitance per unit length), the units cancel out, resulting in a value without units. This property allows for easier comparisons between different materials' electrical characteristics.
What is Relative dielectric constant for vacuum?
YES IT IS. Any quantity which is ratio of two physical quantities having same unit is dimensionless. Dielectric constant is ratio of Permittivty of medium to the permittivity of free space. As Permittivity of medium and permittivity of free space both have same units(F/m ie Farad/meter) dielectric constant becomes dimensionless quantity
What is the relationship between the electric field intensity (E), charge density (q), and permittivity of free space ()?
The relationship between the electric field intensity (E), charge density (q), and permittivity of free space () is given by the equation E q / (). This equation shows that the electric field intensity is directly proportional to the charge density and inversely proportional to the permittivity of free space.
What is the relationship between the electric field (E), permittivity of free space (), and electric charge density () in a given system?
The relationship between the electric field (E), permittivity of free space (), and electric charge density () in a given system is described by Gauss's Law, which states that the electric field (E) at a point in space is directly proportional to the electric charge density () at that point and inversely proportional to the permittivity of free space (). Mathematically, this relationship is represented as E / .
What is the formula for calculating the electric flux through a surface due to a point charge, taking into account the permittivity of free space, represented by the symbol epsilon naught?
The formula for calculating the electric flux through a surface due to a point charge is given by q / , where is the electric flux, q is the charge, and is the permittivity of free space.
What is the conductivity of free space?
Conductivity of free space can be approximated to be equal to the conductivity inside of a vacuum, which is zero.
What is dimension of permittivity of vacumm?
The dimension of permittivity of vacuum, also known as vacuum permittivity or electric constant, is F/m (coulomb per volt per meter). It is denoted by ε₀ and has a value of approximately 8.854 x 10^-12 F/m.
What is difference between absolute permittivity and relative permittivity of medium?
The absolute permittivity of a medium is its relative permittivity multiplied by the vacuum permittivity. The absolute permittivity is a proportionality constant between the electric and displacement field with units of Farad/meters (in SI units). This number is usually very small (e.g. for air: 0.000 000 000 008 85 F/m). The relative permittivity is a unit-less number scaled upward to present nicer numbers (e.g. for air: 1.0005). To get the absolute permittivity from the relative permittivity one should multiply with the vacuum permittivity: 8.85418781... E-12 F/m.
What is the relation between k and permittivity of free space?
The permittivity of free space, denoted by ε₀, is a physical constant that represents the ability of a material to store electrical energy in an electric field. It is related to the Coulomb's constant k (also known as electrostatic constant) by the equation k = 1 / (4πε₀), where k is a proportionality constant in Coulomb's law.
What is unit of absolute permitivity?
The unit of absolute permittivity is farads per meter (F/m). Absolute permittivity, denoted by the symbol ε, measures a material's ability to permit electric field lines. In vacuum, it is represented by ε₀ (the permittivity of free space), which is approximately 8.85 x 10⁻¹² F/m.
What is the dimensional formula for permittivity of free space?
Permittivity =[Ɛo] = [Charge]2 /([Force] [Distance]2) =[TA]2 / [MLT-2] [L]2{[A] is the dimensional formula of electric charge} =[TA]2 / [ML3T-2] =[M-1L-3T(2+2)A2] = [M-1L-3T4A2]
Velocity of travelling wave throgh a cable of relative permittivity 9 is?
The velocity of a wave traveling through a cable is given by the formula ( v = \frac{1}{\sqrt{\mu \epsilon}} ), where ( \mu ) is the permeability of the medium and ( \epsilon ) is the permittivity of the medium. Given that the relative permittivity ( \epsilon_r = 9 ), the permittivity of the medium ( \epsilon ) can be calculated by ( \epsilon = \epsilon_0 \times \epsilon_r ), where ( \epsilon_0 ) is the permittivity of free space. By substituting the values of ( \mu ) and ( \epsilon ) into the formula, the velocity of the wave through the cable can be determined.
