Zero.
Of course not.It varies. Gravitatinal accelaration(g) indirectly propatinal to squared value of distance from centre of earth. g=GM/(R^2) G=universal gravitatinal constant M=mass of earth R=distance from centre
1. what value is assigned to the acceleration due to gravity on earth? The acceleration of gravity on earth is 9.8 meters per second per second. 9.8m/s2 2. what is the initial velocity of an object that is dropped? That would be Vi=0.
The value of g would increase if the compound pendulum is taken nearer to the center of the Earth. This is because gravity is stronger closer to the Earth's surface. Conversely, if the compound pendulum is moved further away from the center of the Earth, the value of g would decrease.
The acceleration due to gravity on Earth is approximately 9.81 m/s^2. This means that any object near the Earth's surface will accelerate towards the ground at this rate due to the force of gravity.
The force that pulls objects towards the center of the Earth is called gravity.
Because the earth is much more heavier than the moon.
The Earth's Core lies at the centre.
No. At the centre of the earth the acceleration due to gravity is ZERO
At the centre of the Earth.
It lies at the center of the Earth.
It lies at the center of the Earth.
It lies at the center of the Earth.
9.8 m/s2 ---------------------- Yes this is the average value of acceleration due to gravity near by the surface of the earth. As we go higher and higher level this g value decreases and becomes almost negligible. Same way as we go deeper and deeper the g value decreases and at the centre of the earth its value becomes zero.
Assuming the ball is a perfect sphere of uniform density, and is suspended from a massless string, the centre of gravity is in the centre of the ball.
As compared to Earth, you mean? If an object doesn't change its shape, the center of mass doesn't depend on gravity - and the center of gravity hardly does so.
isn't in gravity??
gravity pulls us towards the centre (core) of the earth. because bears.