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The units of Coulomb's constant in the equation for the electrostatic force between two charged particles are Newton meters squared per Coulomb squared.

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3mo ago

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Coulombs law is given by the equation:F=kq1*q2/r^2 This means that the force of attration between two particles is = to k(9.11810^9) times the product of their charges divided by the distance apart sqaured. The final units are in Newtons. And in this equation k is a constant given by: 9E9 N*m^2/C^2


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What is the electrical force between a glass bulb with 2.5 micro coulomb of a charge and a rubber bulb with -5.0 micro coulomb of charge when they are saparated by 5.0 centimetres?

You need to use the equation of the electric force is equal to "coulombs constant" mulitplied by charge one multiplied by charge two and all of that divided by the distance of the two charged particles... the equation looks like this...Fe = (K * Q1 * Q2 ) / rIn your problem... (K is always equal to 9*109 N*m2/C2)Q1 = .0000025 CQ2 = -.0000005 Cr = .05 mI converted all the values given into the proper unit. The charges should always be solves while using Coulombs... not micro Coulombs. The distance (r) should always be in meters not centimeters.So just solve it. Your answer should be -2.25 N.


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