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What is the commutator of the operator x with the Hamiltonian in quantum mechanics?
In quantum mechanics, the commutator of the operator x with the Hamiltonian is equal to the momentum operator p.
What is the commutator of the operator x with the momentum operator p raised to the power of n?
The commutator of the operator x with the momentum operator p raised to the power of n is ih-bar times n times p(n-1), where h-bar is the reduced Planck constant.
How do i Derive Position operator in momentum space?
To derive the position operator in momentum space, you can start with the definition of the position operator in position space, which is the operator $\hat{x} = x$. You then perform a Fourier transform on this operator to switch from position space to momentum space. This Fourier transform will yield the expression of the position operator in momentum space $\hat{x}_{p}$.
What is the significance of the commutator x, p2 in quantum mechanics?
In quantum mechanics, the commutator x, p2 represents the uncertainty principle between position (x) and momentum (p). It shows that the precise measurement of both quantities simultaneously is not possible, highlighting the fundamental uncertainty in quantum mechanics.
What is the formula for calculating the angular momentum about a point in a system?
The formula for calculating the angular momentum about a point in a system is L r x p, where L is the angular momentum, r is the position vector from the point to the object, and p is the linear momentum of the object.
What is the commutator of the operator x with the Hamiltonian in quantum mechanics?
In quantum mechanics, the commutator of the operator x with the Hamiltonian is equal to the momentum operator p.
What is the commutator of the operator x with the momentum operator p raised to the power of n?
The commutator of the operator x with the momentum operator p raised to the power of n is ih-bar times n times p(n-1), where h-bar is the reduced Planck constant.
How do i Derive Position operator in momentum space?
To derive the position operator in momentum space, you can start with the definition of the position operator in position space, which is the operator $\hat{x} = x$. You then perform a Fourier transform on this operator to switch from position space to momentum space. This Fourier transform will yield the expression of the position operator in momentum space $\hat{x}_{p}$.
Does the p in p mv mean position?
No it does not. It represents momentum.
What is the significance of the commutator x, p2 in quantum mechanics?
In quantum mechanics, the commutator x, p2 represents the uncertainty principle between position (x) and momentum (p). It shows that the precise measurement of both quantities simultaneously is not possible, highlighting the fundamental uncertainty in quantum mechanics.
What is the formula for calculating the angular momentum about a point in a system?
The formula for calculating the angular momentum about a point in a system is L r x p, where L is the angular momentum, r is the position vector from the point to the object, and p is the linear momentum of the object.
How can you develop quantum mechanical counterpart of classical mechanics for the rate of change of position?
The rate of change of position in Classical mechanics is defined as velocity. The quantum mechanical analog would be more closely related to the momentum operator of the wave equation, which is (in one dimension) p=(h/i*2*pi)*(d/dx); where p is the momentum, h is Planck's constant, i is the square root of negative one, pi is 3.1415...., and d/dx is the partial derivative with respect to space.
What is the relationship between angular momentum and the cross product in physics?
In physics, angular momentum is related to the cross product through the formula L r x p, where L is the angular momentum, r is the position vector, and p is the linear momentum. The cross product is used to calculate the direction of the angular momentum vector in rotational motion.
What is the commutation relation of spin operator 's' and the linear momentum 'p'?
Hi, I haven't done the calculation my self, but I think you may be able to solve this by writing the linear momentum in terms of raising and lowering operators And then writing the spin operator in terms of the raising and lowering operators by the Holstein-Primakoff (H-P) transformation (check the wiki page) Its not going to be enjoyable because your going to have to re-write the H-P representation in terms of an infinite Taylor Series ... but it would be interesting to see if this works out.
How do you solve for momentum?
Momentum, p, is solved by using the momentum equation: p = m*v.
What is the formula of total momentum?
_______________________________________________________ P = m x v P = momentum m= mass v = velocity _______________________________________________________ P t = P 1 x P 2 Total momentum = Momentum 1 X Momentum 2 Total momentum = ( mass x velocity of the first object ) x ( mass x velocity of the second object )
What is the equation to find momuntum?
p=mv where p is momentum, m is mass and v is velocity :)
