The derivative of the moment of inertia with respect to the variable in question is called the rate of change of moment of inertia.
The derivative of the cross product with respect to a given variable is a vector that represents how the cross product changes as that variable changes.
The rate of change is called the derivative in calculus. It measures how a quantity is changing with respect to another variable.
The gradient of a dot product is a vector that represents the rate of change of the dot product with respect to each variable. It is calculated by taking the derivative of the dot product with respect to each variable and combining them into a vector.
The derivative of a function with respect to a vector is a matrix of partial derivatives.
The result of applying the s2 operator to a function is the second derivative of the function with respect to the variable s.
Your question must say 'derivative with respect to what variable.' If you want the derivative with respect to f itself, it is 4.
The derivative of the cross product with respect to a given variable is a vector that represents how the cross product changes as that variable changes.
If it is with respect to t: 1 If it is with respect to some other variable (x for example): (dt)/(dx), which is literally read "the derivative of t with respect to x"
You can differentiate a function when it only contains one changing variable, like f(x) = x2. It's derivative is f'(x) = 2x. If a function contains more than one variable, like f(x,y) = x2 + y2, you can't just "find the derivative" generically because that doesn't specify what variable to take the derivative with respect to. Instead, you might "take the derivative with respect to x (treating y as a constant)" and get fx(x,y) = 2x or "take the derivative with respect to y (treating x as a constant)" and get fy(x,y) = 2y. This is a partial derivative--when you take the derivative of a function with many variable with respect to one of the variables while treating the rest as constants.
With respect to x, the derivative would be:1*Y^3 = Y^3With respect to Y the derivative would be:3*xy^2 - 3In general: the derivative of a variable is defined as: nax^n-1Where n represents the power, a represents the factor and x represents the variable
its 3 if you means the derivative with respect to y. If the question is about deriving implicitly then you could be looking for 3y'
A partial derivative is the derivative of a function of more than one variable with respect to only one variable. When taking a partial derivative, the other variables are treated as constants. For example, the partial derivative of the function f(x,y)=2x2 + 3xy + y2 with respect to x is:?f/?x = 4x + 3yhere we can see that y terms have been treated as constants when differentiating.The partial derivative of f(x,y) with respect to y is:?f/?y = 3x + 2yand here, x terms have been treated as constants.
The derivative with respect to 'x' is 4y3 . The derivative with respect to 'y' is 12xy2 .
in case of derivative w.r.t time first derivative with a variable x gives velocity second derivative gives acceleration thid derivative gives jerk
The rate of change is called the derivative in calculus. It measures how a quantity is changing with respect to another variable.
The gradient of a dot product is a vector that represents the rate of change of the dot product with respect to each variable. It is calculated by taking the derivative of the dot product with respect to each variable and combining them into a vector.
The derivative of 2Y is simply 2. In calculus, when you take the derivative of a constant times a variable (in this case, 2 times Y), the constant remains unchanged. Therefore, the derivative of 2Y with respect to Y is 2.