The derivative with respect to a vector of a function is a vector of partial derivatives of the function with respect to each component of the vector.
The derivative of the cross product with respect to a given variable is a vector that represents how the cross product changes as that variable changes.
To determine the velocity vector from a given position in a physical system, you can calculate the derivative of the position vector with respect to time. This derivative gives you the velocity vector, which represents the speed and direction of motion at that specific point in the system.
The translational speed of a particle at a point is the magnitude of the particle's velocity vector at that point. It is given by the derivative of the position vector with respect to time evaluated at that point.
The result of applying the s2 operator to a function is the second derivative of the function with respect to the variable s.
No, the acceleration of a particle is determined by the second derivative of its position function with respect to time. If the position function is given by x(t) = 119909 + 119862t + 1199052t^2, then the acceleration a(t) would be the derivative of this function with respect to time twice, not just a constant 4C.
The derivative of the cross product with respect to a given variable is a vector that represents how the cross product changes as that variable changes.
To determine the velocity vector from a given position in a physical system, you can calculate the derivative of the position vector with respect to time. This derivative gives you the velocity vector, which represents the speed and direction of motion at that specific point in the system.
The translational speed of a particle at a point is the magnitude of the particle's velocity vector at that point. It is given by the derivative of the position vector with respect to time evaluated at that point.
The result of applying the s2 operator to a function is the second derivative of the function with respect to the variable s.
No, the acceleration of a particle is determined by the second derivative of its position function with respect to time. If the position function is given by x(t) = 119909 + 119862t + 1199052t^2, then the acceleration a(t) would be the derivative of this function with respect to time twice, not just a constant 4C.
the process of finding a function whose derivative is a given function
If you are only given total distance and total time you cannot. If you are given distance as a function of time, then the first derivative of distance with respect to time, ds/dt, gives the velocity. Evaluate this function at t = 0 for initial velocity. The second derivative, d2s/dt2 gives the acceleration as a function of time.
The equation that connects the scalar potential (V) and the vector potential (A) is given by: E = -∇V - ∂A/∂t, where E is the electric field, ∇ is the gradient operator, and ∂t represents the partial derivative with respect to time.
I disagree with the last response. It is implied that the angle you are speaking of is the angle between the x-axis and the vector (this conventionally where the angle of a vector is always measured from). The function you are asking about is the sine function. previous answer: This question is incorrect, first of all you have to tell the angle between vector and what other thing is formed?
Let f be a function and a be the given point you are considering. Then,f(x) - f(a)---------------(x-a)is the difference quotient. If the limit as x approaches a exists, then the function is differentiable at a, or we say the derivative exists at a. If that limit does not exist, then the derivative does not exist at that point.
The first derivative of ( y ) with respect to ( x ), denoted as ( \frac{dy}{dx} ) or ( y' ), represents the rate of change of ( y ) concerning ( x ). It indicates how ( y ) changes when ( x ) changes, providing information about the slope of the function at any given point. To find the first derivative, you apply differentiation rules to the function ( y ).
The gradient of a function, in a given direction, is the change in the value of the function per unit change in the given direction. It is, thus, the rate of change of the function, with respect to the direction. It is generally found by calculating the derivative of the function along the required direction. For a straight line, it is simply the slope. That is the "Rise" divided by the "Run".