The flux through a cube with a charge inside is the total electric field passing through the cube's surface. It is a measure of the electric field strength and direction at the surface of the cube due to the charge inside.
The net electric flux through the cube is the total amount of electric field passing through the surface of the cube.
The electric flux through one face of the cube is the total electric field passing through that face.
Yes, according to Gauss's law, the flux through a closed surface is directly proportional to the charge enclosed by that surface. This is known as the electric flux theorem.
If the surface does not enclose any charge, the electric flux through the surface will be zero. This is because electric flux is a measure of the total electric field passing through a surface, and if there are no charges within the surface, there will be no electric field passing through it.
The formula for calculating the electric flux through a surface due to a point charge is given by q / , where is the electric flux, q is the charge, and is the permittivity of free space.
acc. to gauses law..flux is equal to total charge/e or Q/e as there are six sides of the cube so flux through one surface will be Q/6e
The net electric flux through the cube is the total amount of electric field passing through the surface of the cube.
The electric flux through one face of the cube is the total electric field passing through that face.
You then have an imaginary sphere with twice the volume of the one you imagined only moments earlier. If the point charge is anywhere inside the smaller sphere, and the smaller sphere is anywhere inside the larger one, then the total flux is the same through each of them, although the average flux density through the larger one is less than the average flux density through the smaller one.
The total flux through any closed surface remains constant as long as the totalamount of charge inside it remains constant, regardless of how the surface isshaped, where inside the charge is located or how it's distributed inside.One might even go so far as to say that [ div E = Q ]
Yes, according to Gauss's law, the flux through a closed surface is directly proportional to the charge enclosed by that surface. This is known as the electric flux theorem.
To determine the net electric flux through the torus, we can use Gauss's Law, which states that the electric flux through a closed surface is proportional to the enclosed charge. If the torus does not enclose any charge (meaning the total charge inside is zero), then the net electric flux through the torus will also be zero, regardless of the charges outside it. Given that the charges are ( +100 , \text{nC} ) and ( -6.0 , \text{nC} ), the net charge inside the torus would be ( 100 , \text{nC} - 6.0 , \text{nC} = 94 , \text{nC} ). Therefore, the net electric flux through the torus would be ( \frac{94 , \text{nC}}{\varepsilon_0} ), where ( \varepsilon_0 ) is the permittivity of free space.
If the surface does not enclose any charge, the electric flux through the surface will be zero. This is because electric flux is a measure of the total electric field passing through a surface, and if there are no charges within the surface, there will be no electric field passing through it.
The formula for calculating the electric flux through a surface due to a point charge is given by q / , where is the electric flux, q is the charge, and is the permittivity of free space.
Gauss's Law states that the total electric flux through a closed surface is equal to the charge enclosed by that surface divided by the permittivity of free space. In simpler terms, it describes how the total electric field passing through a closed surface is related to the total charge inside that surface.
The flux through a closed surface enclosing a point charge is independent of the size of the volume it encloses. This is because the electric field due to a point charge follows an inverse square law, resulting in the flux being constant regardless of the size of the enclosing surface.
When a dielectric medium is introduced between the two concentric spheres S1 and S2, the electric flux through S1 will remain unchanged. This is because the electric flux is determined by the charge enclosed within the surface, as described by Gauss's law. Since S1 encloses only charge Q1, the electric flux through S1 is solely dependent on that charge, irrespective of the presence of the dielectric medium. The dielectric affects the electric field within the medium but does not alter the total enclosed charge.