The formula for calculating power loss in a transmission line is Ploss I2 R, where Ploss is the power loss in watts, I is the current flowing through the line in amperes, and R is the resistance of the line in ohms.
The formula for calculating power loss in transmission lines is Ploss I2 R, where Ploss is the power loss, I is the current flowing through the transmission line, and R is the resistance of the transmission line.
For a line of given cross section and material, the power capacity will depend on the current carried, since resistance heating is proportional to (current)2 . For a given power, current is inversely proportional to voltage. Thus raising the voltage from 69 to 390 kv would reduce the current by a factor 69/390 = 0.177 , for the same power transmission, and reduce the heating losses by 0.1772 = 0.031. So you can see why high voltage for long distance lines is essential. Obviously the limiting current on a power line has to be set by economic and practical considerations, but if this is predetermined and set, the limiting power will be that which produces that limiting current, and power = voltage x current. The actual limiting curent will depend on the line cross section, material, and length. The power that a line of a certain voltage can carry is calculated by using the following formula: (2.55×(KV)2 /1000) MW.
The secondary constants of a transmission line are the surge impedance, propagation constant, attenuation constant, and phase constant. These constants determine the behavior of signals traveling through the transmission line and are important for analyzing the performance of the line in terms of signal integrity and power transmission.
Standing waves occur on an open transmission line when there is a mismatch between the line impedance and the load impedance. This causes some of the incident wave to reflect back along the line, interfering with the incident wave and creating areas of constructive and destructive interference known as nodes and antinodes. The presence of standing waves can lead to signal distortion and power losses in the transmission line.
Power to be transmiteed is calculated by using following formula P= (E1*E2/ X)*sin(delta) X= Line reactance = XL-Xc XL= Inductive Reactance Xc=Capacitive Reactance P= Power to be transmitted. Thus , Increament in delta increase P Decreament in X increases P For this we use series, parallel, Combination of both compensation FACTS Devices.
The formula for calculating power loss in transmission lines is Ploss I2 R, where Ploss is the power loss, I is the current flowing through the transmission line, and R is the resistance of the transmission line.
You are calculating the length of a line segment
For a line of given cross section and material, the power capacity will depend on the current carried, since resistance heating is proportional to (current)2 . For a given power, current is inversely proportional to voltage. Thus raising the voltage from 69 to 390 kv would reduce the current by a factor 69/390 = 0.177 , for the same power transmission, and reduce the heating losses by 0.1772 = 0.031. So you can see why high voltage for long distance lines is essential. Obviously the limiting current on a power line has to be set by economic and practical considerations, but if this is predetermined and set, the limiting power will be that which produces that limiting current, and power = voltage x current. The actual limiting curent will depend on the line cross section, material, and length. The power that a line of a certain voltage can carry is calculated by using the following formula: (2.55×(KV)2 /1000) MW.
Formula for straight line depreciation is as follows: Depreciation = (Cost of asset - salvage value) / useful life of asset
TRANSMISSION LINE LOSSES
theriyathu
You don't! That's the whole point of a d.c. transmission line.
performance of transsion line of nigeria power system
Basically an AC transmission line require compensation in terms of reactive power. To push the active power across a transmission line certain amount of reactive power is necessary. In AC transmission line reactive power is generated and consumed. Generator is responsible for the production of reactive and active power both. Than this reactive power is consumed by the load and transmission line. Additional reactive power s supplied by the capacitor. This extra power supplied by the capacitor is termed as reactive power compensation. Requirement of this reactive power is there because reactive power is necessary to maintain the voltage stability.
There are three types of transmission lines of India given follows ---- 1-long transmission line( which is used grid to power suppliers plant ) 2-medium transmission line ( which is used power supplier plant to the industry ) 3- short transmission line ( which is used transformer to the consumers )
Actually surge impedance is present in a transmission line due to the capacitance of transmission line. Now this capacitor attends the reactive power of the transmission line to energise its magnetic flux. now due to the flux the impedance will increase and the power is reactive too. due to the impedance loss is more.
Transmission line efficiency is power at the recieving-end of the line compared to the power at the sending-end of the line and is expressed as a percentage, so this can be formulated. % efficiency = load power (output) / source power (input) x 100 In the line, there are power losses. to calculate this we use the formula: power loss = 3.I2.R where I is current and R is resistance. Now that we have the losses, we know the difference between the input and the output. So, for example, if one had the output value known, then to get the input we just add the loss to the output or if had the input known, just subtract the loss from it to get the output. hope that helps