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What is the formula for centripetal acceleration in terms of velocity squared divided by the radius of the circular path?
The formula for centripetal acceleration is a v2 / r, where "a" is the centripetal acceleration, "v" is the velocity, and "r" is the radius of the circular path.
How do you derive the formula for cetripital acceleration?
That is done via calculus. Specifically, take the movement over a small distance, calculate the change in velocity divided by the time, and figure out what happens if the time interval gets smaller and smaller - as they say in calculus, "get the limit of the acceleration as the time tends towards zero".
How do you calculate the centripetal acceleration of an object?
ac = v2/r, where the variables are: * 'a' is the centripetal acceleration in metres per second per second; * 'v' is the tangential velocity in metres per second; and * 'r' is the radius of motion in metres.
How is the centripetal force formula derived?
The centripetal force formula is derived from Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration. In the case of circular motion, the centripetal force is the force that keeps an object moving in a circular path. This force is directed towards the center of the circle and is equal to the mass of the object multiplied by the square of its velocity divided by the radius of the circle. This relationship is expressed in the formula Fc mv2/r, where Fc is the centripetal force, m is the mass of the object, v is the velocity, and r is the radius of the circle.
Acceleration is the change in velocity divided by what?
Acceleration is the change in velocity divided by the time taken for that change to occur.
What is the formula for centripetal acceleration in terms of velocity squared divided by the radius of the circular path?
The formula for centripetal acceleration is a v2 / r, where "a" is the centripetal acceleration, "v" is the velocity, and "r" is the radius of the circular path.
How do you derive the formula for cetripital acceleration?
That is done via calculus. Specifically, take the movement over a small distance, calculate the change in velocity divided by the time, and figure out what happens if the time interval gets smaller and smaller - as they say in calculus, "get the limit of the acceleration as the time tends towards zero".
How do you calculate the centripetal acceleration of an object?
ac = v2/r, where the variables are: * 'a' is the centripetal acceleration in metres per second per second; * 'v' is the tangential velocity in metres per second; and * 'r' is the radius of motion in metres.
What is the relationship between centripetal force and velocity?
Centripetal force is = mass * velocity square divided by radius
At what angular velocity would the earth have to rotate about its axis for a body at the equator to feel no weight?
You can calculate it yourself, with the formula for acceleration in uniform circular motion. The centripetal acceleration, with circular motion, is v2 / r (velocity squared divided by the radius). Since the Earth's gravitation is about 9.8 meters per second square, solve the equation v2 / r = 9.8, for variable v. r (radius, of the Earth) should be converted to meters. The velocity will be in meters per second.Note that this exercise assumes the Earth is rigid. In practice, if Earth really rotated that fast, it would flatten out a lot, and in fact be torn apart.You can calculate it yourself, with the formula for acceleration in uniform circular motion. The centripetal acceleration, with circular motion, is v2 / r (velocity squared divided by the radius). Since the Earth's gravitation is about 9.8 meters per second square, solve the equation v2 / r = 9.8, for variable v. r (radius, of the Earth) should be converted to meters. The velocity will be in meters per second.Note that this exercise assumes the Earth is rigid. In practice, if Earth really rotated that fast, it would flatten out a lot, and in fact be torn apart.You can calculate it yourself, with the formula for acceleration in uniform circular motion. The centripetal acceleration, with circular motion, is v2 / r (velocity squared divided by the radius). Since the Earth's gravitation is about 9.8 meters per second square, solve the equation v2 / r = 9.8, for variable v. r (radius, of the Earth) should be converted to meters. The velocity will be in meters per second.Note that this exercise assumes the Earth is rigid. In practice, if Earth really rotated that fast, it would flatten out a lot, and in fact be torn apart.You can calculate it yourself, with the formula for acceleration in uniform circular motion. The centripetal acceleration, with circular motion, is v2 / r (velocity squared divided by the radius). Since the Earth's gravitation is about 9.8 meters per second square, solve the equation v2 / r = 9.8, for variable v. r (radius, of the Earth) should be converted to meters. The velocity will be in meters per second.Note that this exercise assumes the Earth is rigid. In practice, if Earth really rotated that fast, it would flatten out a lot, and in fact be torn apart.
What is the net force of a car traveling in a circle?
Disregarding friction, the net force on a car during circular motion is equal to the product of its mass and the square of its velocity, divided by the distance from the center of the circle to the car (the radius). This is also equivalent to the car's centripetal acceleration.
How is the centripetal force formula derived?
The centripetal force formula is derived from Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration. In the case of circular motion, the centripetal force is the force that keeps an object moving in a circular path. This force is directed towards the center of the circle and is equal to the mass of the object multiplied by the square of its velocity divided by the radius of the circle. This relationship is expressed in the formula Fc mv2/r, where Fc is the centripetal force, m is the mass of the object, v is the velocity, and r is the radius of the circle.
Acceleration is the change in velocity divided by what?
Acceleration is the change in velocity divided by the time taken for that change to occur.
Why does an object in uniform circular motion exhibits acceleration when its speed is constant?
Acceleration is defined as the change in velocity divided by the time ora = (vf - vi)/tVelocity measures the speed and the direction of an object.In uniform circular motion, the object has the same speed but it is always changing direction and so, by the definition of acceleration, the object is considered accelerating. If this acceleration doesn't exist, the object would move in a straight line according to Newton's laws of motion.
How is centripetal force related to newtons 2 force?
With regard to Newton's First Law only, about all you could say is that if an objecthas no centripetal force acting on it, then it continues in constant, uniform motion.
Is acceleration equal to the initial velocity minus the final velocity and then divided by time?
No, acceleration is calculated as the change in velocity divided by time. It is the rate at which the velocity of an object changes. Mathematically, acceleration is represented as (final velocity - initial velocity) / time.
How do you find acceleration using velocity and time?
Acceleration = (change in velocity) divided by (time for the change)
