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The formula for the potential energy of a simple harmonic oscillator in terms of the equilibrium position and the angle theta is U 1/2 k (x2 (L - x)2), where U is the potential energy, k is the spring constant, x is the displacement from the equilibrium position, and L is the length of the spring at equilibrium.

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What is the expectation value of potential energy for a harmonic oscillator?

The expectation value of potential energy for a harmonic oscillator is equal to half of the oscillator's spring constant multiplied by the square of the oscillator's displacement from its equilibrium position.


Which energy stored in harmonic oscillator?

In a harmonic oscillator, the energy is stored in two forms: potential energy and kinetic energy. The potential energy is due to the displacement of the oscillator from its equilibrium position, while the kinetic energy is due to the motion of the oscillator. The total energy of a harmonic oscillator remains constant as it oscillates back and forth between potential and kinetic energy.


What is the expectation value of position for a harmonic oscillator system with respect to the variable x?

The expectation value of position for a harmonic oscillator system with respect to the variable x is the average position that the oscillator is most likely to be found at when measured.


What is the expectation value of position in the harmonic oscillator system?

In the harmonic oscillator system, the expectation value of position is the average position that a particle is most likely to be found at. It is calculated as the integral of the position probability distribution function multiplied by the position variable.


How can amplitude be measured?

Amplitude can be measured by calculating the maximum displacement of a wave from its equilibrium position. For example, in a simple harmonic oscillator, amplitude is measured as the distance from the equilibrium position to the maximum displacement of the oscillator. In a wave, amplitude can be measured as the height of the wave from the resting position to the peak.

Related Questions

What is the expectation value of potential energy for a harmonic oscillator?

The expectation value of potential energy for a harmonic oscillator is equal to half of the oscillator's spring constant multiplied by the square of the oscillator's displacement from its equilibrium position.


Which energy stored in harmonic oscillator?

In a harmonic oscillator, the energy is stored in two forms: potential energy and kinetic energy. The potential energy is due to the displacement of the oscillator from its equilibrium position, while the kinetic energy is due to the motion of the oscillator. The total energy of a harmonic oscillator remains constant as it oscillates back and forth between potential and kinetic energy.


What is the expectation value of position for a harmonic oscillator system with respect to the variable x?

The expectation value of position for a harmonic oscillator system with respect to the variable x is the average position that the oscillator is most likely to be found at when measured.


What is the expectation value of position in the harmonic oscillator system?

In the harmonic oscillator system, the expectation value of position is the average position that a particle is most likely to be found at. It is calculated as the integral of the position probability distribution function multiplied by the position variable.


How can amplitude be measured?

Amplitude can be measured by calculating the maximum displacement of a wave from its equilibrium position. For example, in a simple harmonic oscillator, amplitude is measured as the distance from the equilibrium position to the maximum displacement of the oscillator. In a wave, amplitude can be measured as the height of the wave from the resting position to the peak.


What is the equilibrium position in simple harmonic motion?

The equilibrium position in simple harmonic motion is the point where the oscillating object is at rest, with no net force acting on it. It is the position where the object naturally tends to stay when not disturbed.


What is the dispalment of an object in shm when pe and ke are equal?

When the potential energy (PE) and kinetic energy (KE) of an object in simple harmonic motion (SHM) are equal, the object is at its equilibrium position. At this point, the displacement of the object from its equilibrium position is zero.


How does a harmonic oscillator behave in an electric field?

A harmonic oscillator in an electric field experiences a force that depends on its position. This force causes the oscillator to move back and forth in a periodic manner, similar to its behavior in the absence of an electric field. The presence of the electric field can alter the frequency and amplitude of the oscillator's motion, leading to changes in its behavior.


Is the acceleration of a simple harmonic oscillator ever zero if so where?

Yes; the acceleration is zero when the velocity is at its maximum, that is, at the equilibrium position. Since the force and hence the acceleration always act TOWARDS the equilibrium position (because it's a restorative force), then the force and acceleration must change their sign as the mass crosses the e.p., and therefore must be zero instantaneously at the e.p.


What is moment of harmonic rest is called?

The moment of harmonic rest in a vibrating system is called equilibrium position. It is the position where the restoring force is zero and the system is in a state of balance.


In simple harmonic motion the restoring force must be proportional to the?

displacement


What is the displacement of an object is SHM when kinetic and potential energies are equal?

In **simple harmonic motion (SHM)**, the **kinetic energy (KE)** and **potential energy (PE)** of the system vary with time, but their **sum is constant** (the total mechanical energy). We are asked to find the **displacement** of the object when: > **Kinetic energy = Potential energy** **Key Idea:** In SHM, the expressions for energies are: **Total energy, ( E = \frac{1}{2}kA^2 )** **Kinetic energy, ( KE = \frac{1}{2}k(A^2 - x^2) )** **Potential energy, ( PE = \frac{1}{2}kx^2 )** Where: ( k ) = spring constant, ( A ) = amplitude, ( x ) = displacement from equilibrium. **Step-by-step:** Set ( KE = PE ): [ \frac{1}{2}k(A^2 - x^2) = \frac{1}{2}kx^2 ] Cancel out ( \frac{1}{2}k ): [ A^2 - x^2 = x^2 ] [ A^2 = 2x^2 ] [ x^2 = \frac{A^2}{2} ] [ x = \pm \frac{A}{\sqrt{2}} = \pm \frac{\sqrt{2}}{2}A ] ✅ **Final Answer:** > The displacement is: > [ > x = \pm \frac{A}{\sqrt{2}} = \pm 0.707A > ] At this displacement, the kinetic and potential energies are **equal**.

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