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The speed of a point on the rim of an object in motion is determined by the object's rotational speed and the distance of the point from the center of rotation. This speed is calculated using the formula: speed radius x angular velocity.

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3mo ago

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How does the tapered rim of the wheel on a railroad train allow one part of the rim to have a greater tangential speed than another part when it is rolling on a track?

Tangential speed, unlike rotational speed, depends on radial distance. At the very center of the rotating platform, you have no speed at all; you merely rotate. But, as you approach the edge of the platform, you find yourself moving faster and faster. Tangential speed is directly proportional to distance from the axis for any given rotational speed. (https://sites.google.com/site/reyesmityville/physics)


Example of circular motion?

A common example of circular motion is a ball being swung in a circle on the end of a string. As the ball moves in a circular path, it experiences centripetal acceleration directed towards the center of the circle. This type of motion arises when an object constantly changes direction while maintaining a constant speed.


What is the tangential speed of a passenger on a Ferris wheel that has a radius of 15 m and rotates once in 40 s?

The tangential speed of a point on the outer rim of the wheel is (circumference) divided by (time per rotation) = (30 pi) / (40) = 2.356 meters per second. (rounded) The passenger's tangential speed depends on how close to the rim he sits. Anywhere on the wheel, it has to be 2.356 meters per second or less.


A tappered cup rolled on a flat surface makes a circular path What does this tell you about the tangential speed of the rim of the wide end of the cup compared with that of the rim of the narrow end?

The tangential speed of the rim of the wide end of the cup is greater than that of the narrow end because the circular path covered by the wide end is larger than that covered by the narrow end. The rim of the wide end has to cover a greater distance in the same amount of time, hence its tangential speed is higher.


An industrial flywheel has a greater rotational inertia when most of its mass is?

On the outer rim. Further away from the axis point.

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I have to assume that you are referring to the Rim of the wheel where the seats are attached. That being the case, the circular motion of the wheel's rim creates Centrifugal and Centripetal forces. These forces act against each other along the radius of the wheel, at every point on its circumference. Unless the wheel rim flies apart, the two forces are exactly in balance. The acceleration is caused because the points on the rim are constantly changing direction as the wheel rotates. In order for a real object to change its direction of motion, a Force is needed. Remember that Force = Mass x Acceleration. So an Acceleration is needed to generate the Force to change the direction of any point on the rotating wheel. That acceleration is felt by the riders of the wheel as being lifted off the seat, or pushed into the seat...depending on their position relative to the ground (force of Gravity), and the speed of the Wheel.


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How does the tapered rim of the wheel on a railroad train allow one part of the rim to have a greater tangential speed than another part when it is rolling on a track?

Tangential speed, unlike rotational speed, depends on radial distance. At the very center of the rotating platform, you have no speed at all; you merely rotate. But, as you approach the edge of the platform, you find yourself moving faster and faster. Tangential speed is directly proportional to distance from the axis for any given rotational speed. (https://sites.google.com/site/reyesmityville/physics)