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How much work does Paul's force do during a displacement of the crate that is 12.0 m?
The work done by Paul's force is given by the formula Work = Force x Distance x cos(theta), where theta is the angle between the force and the direction of displacement. If the force is in the same direction as the displacement, then theta = 0 and the work done is simply Force x Distance. If the angle is not given, assuming theta = 0, the work done is the force times the distance.
How do you calculate work done an object?
Work done is calculated by multiplying the force applied to an object by the distance over which the force is applied in the direction of the force. Mathematically, work done (W) = force (F) * distance (d) * cos(theta), where theta is the angle between the force and the direction of motion.
How much work is done if the sled moves 10 horizontally?
The work done on the sled is given by the formula: work = force x distance x cos(theta), where theta is the angle between the force and the direction of motion. If the force is applied horizontally and moves the sled horizontally, the angle theta is 0, and the work done is simply force x distance.
How is the work done on an object calculated?
Work done on an object is calculated by multiplying the force applied to the object by the distance the object moves in the direction of the force. The formula for work done is: work = force x distance x cos(theta), where theta is the angle between the force and the direction of motion.
How much work is done by a force of 60 n that moves an object 6 meters?
The work done by a force can be calculated using the formula: Work = Force x Distance x cos(theta), where theta is the angle between the force and the direction of motion. Assuming the force is in the direction of motion (theta = 0), the work done would be 360 Joules (60 N * 6 m).
How much work does Paul's force do during a displacement of the crate that is 12.0 m?
The work done by Paul's force is given by the formula Work = Force x Distance x cos(theta), where theta is the angle between the force and the direction of displacement. If the force is in the same direction as the displacement, then theta = 0 and the work done is simply Force x Distance. If the angle is not given, assuming theta = 0, the work done is the force times the distance.
How do you calculate work done an object?
Work done is calculated by multiplying the force applied to an object by the distance over which the force is applied in the direction of the force. Mathematically, work done (W) = force (F) * distance (d) * cos(theta), where theta is the angle between the force and the direction of motion.
How much work is done if the sled moves 10 horizontally?
The work done on the sled is given by the formula: work = force x distance x cos(theta), where theta is the angle between the force and the direction of motion. If the force is applied horizontally and moves the sled horizontally, the angle theta is 0, and the work done is simply force x distance.
How is the work done on an object calculated?
Work done on an object is calculated by multiplying the force applied to the object by the distance the object moves in the direction of the force. The formula for work done is: work = force x distance x cos(theta), where theta is the angle between the force and the direction of motion.
How much work is done by a force of 60 n that moves an object 6 meters?
The work done by a force can be calculated using the formula: Work = Force x Distance x cos(theta), where theta is the angle between the force and the direction of motion. Assuming the force is in the direction of motion (theta = 0), the work done would be 360 Joules (60 N * 6 m).
How did you determined that work is done?
Work is done when a force acts upon an object to cause it to move in the direction of the force. Mathematically, work done is calculated by the formula: Work = Force x Distance x cos(theta), where theta is the angle between the force and the direction of motion. So, when a force is applied on an object to move it a certain distance, work is done.
How do you solve to work done?
Work done is calculated by multiplying the force applied to an object by the distance over which the force is applied in the direction of the force. The formula is: Work = Force x Distance x cos(theta), where theta is the angle between the force and the direction of motion. Work is measured in joules (J).
Work is done when a force is used to?
Work is done when a force is used to displace an object in the direction of the force. This creates a transfer of energy to the object, resulting in work being done on the object. The formula for work is W = F * d * cos(theta), where F is the force applied, d is the displacement, and theta is the angle between the force and the displacement.
What is the work done if we apply a 1.2N force and move 4m in the direction of force?
what is the work done if we apply a 1.2N force and we move 4 m in the direction of force
To calculate work done on an object .?
Work done on an object is calculated by multiplying the force applied to the object by the distance the object moves in the direction of the force. The formula for work done is: Work = Force x Distance x cos(theta), where theta is the angle between the force and the direction of motion. Work is typically measured in joules (J).
Does the tension in the string of a swinging pendulum do any work?
No, the tension in the string of a swinging pendulum does not do any work. The tension force acts perpendicular to the direction of motion, so it does not apply a force in the direction of displacement. This means that no work is done by the tension force on the pendulum.
On the pail when the person is holding the pail by the force F is moving forword how much work is done?
The work done when a person is holding a pail and moving forward by a force F is given by the formula: Work = Force x Distance x cos(theta), where theta is the angle between the force and the direction of motion. If the force is directly in line with the direction of motion (theta = 0), then all of the force is doing work. If the force is at an angle to the direction of motion, only the component of the force in the direction of motion contributes to the work done.
