The two forces involved in a stretched spring are the restoring force, which acts to bring the spring back to its equilibrium position, and the applied force, which is the external force that stretches the spring.
The potential energy of an object that is stretched is known as elastic potential energy. This type of energy is stored in objects that are stretched or compressed, such as a spring or a rubber band. It is calculated by the equation PE = 1/2 kx^2, where k is the spring constant and x is the displacement from the equilibrium position.
Elastic potential energy is the energy stored in an elastic material (like a spring or rubber band) when it is stretched or compressed. It is calculated as 1/2 * k * x^2, where k is the spring constant and x is the displacement from the equilibrium position.
A spring contains potential energy, specifically elastic potential energy. As the spring is compressed or stretched, potential energy is stored within it. This energy is released when the spring returns to its rest position.
The energy required to stretch or compress a spring is potential energy, which is stored in the spring as it is deformed from its equilibrium position. This potential energy is proportional to the amount the spring is stretched or compressed and can be calculated using the formula 1/2kx^2, where k is the spring constant and x is the displacement from equilibrium.
A stretched rubber band and a compressed spring both contain strain energy.
The potential energy of an object that is stretched is known as elastic potential energy. This type of energy is stored in objects that are stretched or compressed, such as a spring or a rubber band. It is calculated by the equation PE = 1/2 kx^2, where k is the spring constant and x is the displacement from the equilibrium position.
Elastic potential energy is the energy stored in an elastic material (like a spring or rubber band) when it is stretched or compressed. It is calculated as 1/2 * k * x^2, where k is the spring constant and x is the displacement from the equilibrium position.
name tge two forces involved in the attle of pasir panjang in world war 2 ?
A spring contains potential energy, specifically elastic potential energy. As the spring is compressed or stretched, potential energy is stored within it. This energy is released when the spring returns to its rest position.
The energy required to stretch or compress a spring is potential energy, which is stored in the spring as it is deformed from its equilibrium position. This potential energy is proportional to the amount the spring is stretched or compressed and can be calculated using the formula 1/2kx^2, where k is the spring constant and x is the displacement from equilibrium.
You didn't give me any values, but I can give you a formula that will answer your question. The force exerted by a spring is given as F = -KX, where K is the spring constant and x is the distance the spring is compressed or stretched. When the spring is compressed fully, it has a force F. When the spring is at equilibrium(aka not stretched), it has a force of zero. We can average these to say that the Average force of a spring is F = 1/2 -KX. We can now substitute the -1/2 KX into the equation F = ma. This yeilds -1/2 KX = ma. Solve for acceleration, we get (-1/2 KX)/m = a. Multiply this quantity by the amount of time the spring pushed on the object, and you have your velocity. Hope this helps whoever asked. --An AP Physics Student Bored in Study Hall
A stretched rubber band and a compressed spring both contain strain energy.
A spring stretches because the coiled spring stores potential energy. This energy is released as the spring is stretched and returns to its original shape. Over a period of time, the spring becomes worn and loses the potential energy.
Elastic potential energy is the energy stored in an object when it is compressed or stretched, such as in a spring or rubber band. It is calculated using the equation (PE = \frac{1}{2} kx^2), where (k) is the spring constant and (x) is the displacement from the equilibrium position.
The two forces involved in using a machine are the input force, which is the force applied to the machine, and the output force, which is the force exerted by the machine to do work. The relationship between these forces determines the machine's mechanical advantage.
Potential energy in a spring is the energy stored in the spring when it is compressed or stretched from its equilibrium position. It is commonly calculated using the equation P.E. = 1/2 k x^2, where k is the spring constant and x is the displacement from the equilibrium position.
Assuming the spring obeys Hooke's Law, we can use the formula F = kx, where F is the force, k is the spring constant, and x is the displacement. Since the spring is stretched by 2cm (or 0.02m) when supporting a 1kg load, we can calculate the spring constant k. With a 1kg load, F = 1kg * 9.8m/s^2 = 9.8N. Therefore, k = F / x = 9.8N / 0.02m = 490N/m. Now, for a 3kg load, F = 3kg * 9.8m/s^2 = 29.4N. Using the spring constant k = 490N/m, we can rewrite F = kx as 29.4N = 490N/m * x. Solving for x, we find that the spring will be stretched by 0.06m (or 6cm) when supporting a 3kg load.