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What is the equation for a vertical spring-mass system?
The equation for a vertical spring-mass system is given by: m a -k x where: m mass of the object a acceleration of the object k spring constant x displacement from the equilibrium position
What is the mass at standard conditions if the weight of an object is 50 pounds?
An object that weighs 50 pounds at standard conditions has a mass of 22.680 kilograms.
Is the period of a vibrating spring linearly affected by the mass of the attached object?
Let a mass m be attached to the end of a spring with spring constant k. The spring extends and comes to rest with an equilibrium extension e. At equilibrium; Weight = Force exerted by spring => mg = ke -------- 1 Suppose the spring is displaced through a displacement x downwards from its equilibrium position: Resolving vertically, we have; Resultant force on mass = Force exerted by spring - Weight of mass => ma = k(e + x) - mg ------- 2 From 1, we have: ma = mg + kx - mg => a = (k/m)x Since a is proportional to displacement from equilibrium position, the oscillation is simple harmonic. So, (angular velocity)2 = (k/m) => 2pi/T = (k/m)1/2 => T = 2pi (m/k)1/2 This equation shows that the time period is proportional to the square root of the mass of the attached object.
What quantities are needed to find the mass density of an object?
To find the mass density of an object, you need to know the mass of the object and its volume. Mass density (ρ) is calculated as the mass (m) of the object divided by its volume (V): ρ = m/V.
What is the formula for calculating the linear mass density of a one-dimensional object?
The formula for calculating the linear mass density of a one-dimensional object is mass divided by length. It is represented as m/L, where is the linear mass density, m is the mass of the object, and L is the length of the object.
What is the equation for a vertical spring-mass system?
The equation for a vertical spring-mass system is given by: m a -k x where: m mass of the object a acceleration of the object k spring constant x displacement from the equilibrium position
What is the mass at standard conditions if the weight of an object is 50 pounds?
An object that weighs 50 pounds at standard conditions has a mass of 22.680 kilograms.
Is the period of a vibrating spring linearly affected by the mass of the attached object?
Let a mass m be attached to the end of a spring with spring constant k. The spring extends and comes to rest with an equilibrium extension e. At equilibrium; Weight = Force exerted by spring => mg = ke -------- 1 Suppose the spring is displaced through a displacement x downwards from its equilibrium position: Resolving vertically, we have; Resultant force on mass = Force exerted by spring - Weight of mass => ma = k(e + x) - mg ------- 2 From 1, we have: ma = mg + kx - mg => a = (k/m)x Since a is proportional to displacement from equilibrium position, the oscillation is simple harmonic. So, (angular velocity)2 = (k/m) => 2pi/T = (k/m)1/2 => T = 2pi (m/k)1/2 This equation shows that the time period is proportional to the square root of the mass of the attached object.
What quantities are needed to find the mass density of an object?
To find the mass density of an object, you need to know the mass of the object and its volume. Mass density (ρ) is calculated as the mass (m) of the object divided by its volume (V): ρ = m/V.
What is the formula for calculating the linear mass density of a one-dimensional object?
The formula for calculating the linear mass density of a one-dimensional object is mass divided by length. It is represented as m/L, where is the linear mass density, m is the mass of the object, and L is the length of the object.
Which equation can be used to solve for the mass of the object?
Thanks to Isaac Newton's Second Law of Motion, one can determine the mass of an object if he or she knows both the force acting upon the object and the acceleration of the object. Newton's equation is as follows: F = ma; where "F" is the force acting upon the object, "m" is the mass of the object. and "a" is the acceleration of the object. Solving for "m", the equation can be rewritten as: m = F/m. Substitute force for "F", and acceleration for "a", and you can solve for the mass of the object.
What is a constant force F is applied to an object with mass M?
When a constant force F is applied to an object with mass M, it will result in an acceleration of the object according to Newton's second law, F = ma, where F is the force, m is the mass of the object, and a is the acceleration. The object will continue to accelerate as long as the force is applied.
If a net force of 120N gives an object an acceleration of 1.5 m s s what is the mass of the object?
The mass of the object can be calculated using the formula F = ma, where F is the net force, m is the mass, and a is the acceleration. Rearranging the formula to solve for mass, we get m = F / a. Plugging in the values given, mass = 120N / 1.5 m/s^2 = 80 kg. So, the mass of the object is 80 kg.
What is the equation for newtons second law?
The unbalanced force acting on an object equals the object's mass times it acceleration. The equation to find force is as follows.Force=mass*accelerationf=mv
What does the m stand for in the formula for kinetic energy?
The "m" in the formula for kinetic energy, K = 1/2mv^2, represents the mass of the object in motion.
What does the m stand for in kinetic energy?
The "m" in kinetic energy stands for mass. It represents the mass of the object in motion and is part of the equation for kinetic energy: KE = 1/2 * m * v^2, where KE is kinetic energy, m is mass, and v is velocity.
What influences the kinetic energy of an object?
The mass and velocity of an object determine the kinetic energy of an object. The equation for kinetic energy is KE = 1/2mv2, where m is mass in kg, and v is velocity in m/s.
