we know that according to law of conservation of energy
"Energy can neither be created nor destroy, but it can only change from one form to another "
just like this
before the stone was being thrown , it possessed P.E (potential energy) when when it was thrown it's P.E was converted into K.E (kinetic energy) and when it striked the ground it's K.E was converted again into P.E.
As the stone falls off the tabletop, its potential energy decreases while its kinetic energy increases. At the moment it leaves the tabletop, it has maximum potential energy and zero kinetic energy. As it falls, its potential energy is converted into kinetic energy until it reaches the ground and all potential energy is transformed into kinetic energy.
As the stone falls, it possesses potential energy due to its height above the ground. This potential energy is then converted into kinetic energy as the stone accelerates towards the ground. At any point during the fall, the stone possesses both potential and kinetic energy simultaneously.
As the stone falls, its potential energy decreases due to the decrease in height above the ground. At the same time, its kinetic energy increases as it gains speed while falling. The total mechanical energy (sum of potential and kinetic energy) of the stone remains constant in the absence of external forces like air resistance.
The stone initially possesses gravitational potential energy due to its height above the ground. As it falls, this potential energy is converted into kinetic energy associated with its motion. Upon impact with the ground, this kinetic energy transforms into thermal and sound energy, dissipating into the surroundings.
The stone has potential energy due to its position above the ground. As gravity pulls the stone down, this potential energy is converted to kinetic energy.
As the stone falls off the tabletop, its potential energy decreases while its kinetic energy increases. At the moment it leaves the tabletop, it has maximum potential energy and zero kinetic energy. As it falls, its potential energy is converted into kinetic energy until it reaches the ground and all potential energy is transformed into kinetic energy.
As the stone falls, it possesses potential energy due to its height above the ground. This potential energy is then converted into kinetic energy as the stone accelerates towards the ground. At any point during the fall, the stone possesses both potential and kinetic energy simultaneously.
As the stone falls, its potential energy decreases due to the decrease in height above the ground. At the same time, its kinetic energy increases as it gains speed while falling. The total mechanical energy (sum of potential and kinetic energy) of the stone remains constant in the absence of external forces like air resistance.
The stone initially possesses gravitational potential energy due to its height above the ground. As it falls, this potential energy is converted into kinetic energy associated with its motion. Upon impact with the ground, this kinetic energy transforms into thermal and sound energy, dissipating into the surroundings.
The stone has potential energy due to its position above the ground. As gravity pulls the stone down, this potential energy is converted to kinetic energy.
Sitting on the table the stone has potential energy, relative to the ground, of weight times height, mgh. It has zero kinetic energy so its total energy is E = 0 + mgh. When it begins falling it loses potential energy (as it loses height) and gains kinetic energy ( as it picks up speed) so the sum stays the same as initially E = KE + PE = mgh. Just before it hits the ground all of its potential energy is gone and has been transformed into kinetic energy. So the kinetic energy at the bottom (1/2)mv^2 will equal the potential energy at the top.
No. For example a falling stone is converting potential energy of gravitational attraction into kinetic energy, and there is no elastic energy.
A falling stone.
I think what is being suggested here is that the kinetic energy of the stone will have reduced considerably by the time it reaches the bird 7 meters up, but the potential energy will have increased correspondingly. Suppose the stone just reaches 7 meters, its kinetic energy will have all been turned into potential energy, but the bird will only obtain that PE if the stone sticks to it, otherwise the stone just falls back to earth and regains its kinetic energy before impact.
It's exactly the gravitational potential energy that the stone had, relativeto the ground, before it was dropped:M G H = (9.8) x (the stone's mass) x (the height of the building) joules
Sitting on the table the stone has potential energy, relative to the ground, of weight times height, mgh. It has zero kinetic energy so its total energy is E = 0 + mgh. When it begins falling it loses potential energy (as it loses height) and gains kinetic energy ( as it picks up speed) so the sum stays the same as initially E = KE + PE = mgh. Just before it hits the ground all of its potential energy is gone and has been transformed into kinetic energy. So the kinetic energy at the bottom (1/2)mv^2 will equal the potential energy at the top.
The stone would have a combination of potential and kinetic energy halfway down the hill. The potential energy would decrease as the stone moves lower, while the kinetic energy would increase as the stone gains speed.