Assuming normal color vision for the observer, a red object in red light appears red. But that's so obvious that I suspect there may be another unstated context for the question. For example, if you are photographing an object with a panchromatic black and white film, you will get different results in different lighting. Since an object reflects its own color and absorbs others, a red object in blue or green light would be less or non-reflective, so will appear very dark in a photographic print. In red light (because it reflects red), it will appear light. That same principle of reflection and absorption explains why, in some very old photographs made with films that were not sensitized to red wavelengths, women wearing red lipstick appeared to have very black lips. The red was reflected, but made no exposure on the red-blind film. There may be other contexts for the question, but this should give you an idea how to treat them.
A "green" object is called "green" because that's the only color of light it reflects, and it absorbs any other color. If orange light is shining on it, then there's no light for it to reflect, and it looks black to you.
An object appears a certain color to you because it reflects that color of light and absorbs other colors of light. For example, a white object appears white because it reflects all colors of visible light (red, orange, yellow, green, blue, indigo, violet). A black object appears black because it absorbs all of these colors--and as a result, none of those colors are reflected back to your eyes. Under white light, the object appears yellow-green because it reflects both yellow and green light and absorbs all other colors. (Remember, white light has all colors of visible light in it). If only green light is present, there's only green light for it to reflect--so it will appear green. If you shined yellow light on it only, it would be yellow. If you shined yellow and green light, it would appear yellow-green again. It you shined red and blue light on it, it would appear black, because it absorbs both of those colors.
You would see that the lemon appears yellow when a green light is shined on it. Yellow is the color that the lemon reflects back to your eyes.
A green object under green light would appear its original color and shade of green. When an object is illuminated by light of the same color, no new colors are absorbed or reflected, resulting in the object appearing unchanged.
If an object is white in sunlight it will be green in green light. A white object reflects all wavelengths (colors) of light that shine on it. If only green light shines on it, that color will be reflected and the object will look green.
A "green" object is called "green" because that's the only color of light it reflects, and it absorbs any other color. If orange light is shining on it, then there's no light for it to reflect, and it looks black to you.
When light is shined on a cyan object, it will appear cyan as long as the light source contains both blue and green wavelengths, which are the colors that make up cyan. If the light is white, the cyan object will reflect the blue and green light and thus still appear cyan. However, if the light is only red, the cyan object will appear black because it cannot reflect that color.
An object appears a certain color to you because it reflects that color of light and absorbs other colors of light. For example, a white object appears white because it reflects all colors of visible light (red, orange, yellow, green, blue, indigo, violet). A black object appears black because it absorbs all of these colors--and as a result, none of those colors are reflected back to your eyes. Under white light, the object appears yellow-green because it reflects both yellow and green light and absorbs all other colors. (Remember, white light has all colors of visible light in it). If only green light is present, there's only green light for it to reflect--so it will appear green. If you shined yellow light on it only, it would be yellow. If you shined yellow and green light, it would appear yellow-green again. It you shined red and blue light on it, it would appear black, because it absorbs both of those colors.
You would see that the lemon appears yellow when a green light is shined on it. Yellow is the color that the lemon reflects back to your eyes.
A green object under green light would appear its original color and shade of green. When an object is illuminated by light of the same color, no new colors are absorbed or reflected, resulting in the object appearing unchanged.
If an object is white in sunlight it will be green in green light. A white object reflects all wavelengths (colors) of light that shine on it. If only green light shines on it, that color will be reflected and the object will look green.
The object would be black, because red cannot reflect green light so no colour is reflected of the object.
When a blue light is shined onto a different color, the object will absorb some of the blue light and reflect the rest. The color that we perceive is the result of the wavelengths of light that are reflected off the object. Different colors absorb and reflect light in unique ways, leading to the variety of colors we see around us.
Since an object is observed as the color(s) it reflects, a green object absorbs all colors and reflects green.
A green object absorbs all colors of light except for green. When white light, which contains all colors of the visible spectrum, hits the object, the green pigment in the object absorbs all colors except green, which is reflected off the object. This reflected green light is what we perceive with our eyes, giving the object its green color.
When light hits a green object, the object absorbs all the colors in the light spectrum except for green. Green is reflected off the object, which is why we perceive it as green. This reflection is what gives the object its color.
An opaque object that absorbs green light would appear magenta, which is the complementary color to green. This is because the object absorbs green light and reflects red and blue wavelengths, which combine to produce magenta.