You can't see it because a blue filter only lets blue light in, and red is made up of just red light, no blue, so none passes through (or it gets reflected, can't remember which)
When shining a red light through a blue filter, the light that passes through will appear black. This is because the blue filter only allows blue light to pass through, while blocking red light.
Nothing comes through. A red light emits no blue light, and a blue filter allows only blue light to pass ... that's why when you look at it, you say to yourself "Hey! That filter looks blue. I'll call it a 'blue filter'."
If you put a blue filter in front of a red filter, the blue filter would block all the red light and only allow blue light to pass through. The red filter would then block all the blue light that passed through the blue filter. This would result in no light passing through the filters, so you wouldn't see any color.
If blue light passes through a blue filter, the light will be transmitted through the filter because the filter is designed to allow blue light to pass through while absorbing other colors of light. The blue filter selectively transmits blue light and blocks other colors of light.
A cyan colored surface will reflect any blue or green light that is incident. The green filter will remove all colors of light passing through it except green. The book is illuminated with only blue light. Draw your conclusion.
When shining a red light through a blue filter, the light that passes through will appear black. This is because the blue filter only allows blue light to pass through, while blocking red light.
Nothing comes through. A red light emits no blue light, and a blue filter allows only blue light to pass ... that's why when you look at it, you say to yourself "Hey! That filter looks blue. I'll call it a 'blue filter'."
When red light passes through a blue filter, it appears dark or nearly black. This is because the blue filter only allows blue light to pass through and absorbs other colors, including red. Since red light cannot be transmitted through the blue filter, it effectively gets blocked.
black because blue light cannot pass through a yellow filter
If you put a blue filter in front of a red filter, the blue filter would block all the red light and only allow blue light to pass through. The red filter would then block all the blue light that passed through the blue filter. This would result in no light passing through the filters, so you wouldn't see any color.
If blue light passes through a blue filter, the light will be transmitted through the filter because the filter is designed to allow blue light to pass through while absorbing other colors of light. The blue filter selectively transmits blue light and blocks other colors of light.
A cyan colored surface will reflect any blue or green light that is incident. The green filter will remove all colors of light passing through it except green. The book is illuminated with only blue light. Draw your conclusion.
Blue is a primary light colour so it exists all the time. You cannot make it from any other colour. Shine a bright white light through a prism or look at a rainbow, you can see the "blue" part of the visible spectrum. Shine a light through a "blue" filter you can see the blue colour on a substrate. Between 400 and 500 nano meters frequency is where blue can be found
Blue is a primary light colour so it exists all the time. You cannot make it from any other colour. Shine a bright white light through a prism or look at a rainbow, you can see the "blue" part of the visible spectrum. Shine a light through a "blue" filter you can see the blue colour on a substrate. Between 400 and 500 nano meters frequency is where blue can be found
blue
I think you would see blue.I say that, because I'm thinking to myself: "WHAT MAKES THE FILTER BLUE ? ! ? !"
When white light passes through a blue filter, the filter absorbs most of the colors in the white light spectrum and only allows blue light to pass through. As a result, the white light will appear blue after passing through the filter.