orange :) i think
In blue light, a yellow object would appear dark or black because yellow absorbs blue light and reflects other colors. This means that the object wouldn't reflect any of the blue light, making it appear dark.
If the light is or contains the colour the object it is striking, then the object will appear to be the colour it originally is. If the light is not or does not contain the colour the object it is striking, then object will appear black. This is because an object will only reflect the light that is the same colour as it, all other light is absorbed. For example: Red, yellow, magenta, and white light will make a red object appear red as they all contain red light. Blue, green and cyan light will make a red object appear black.
It would look like a very, very, very, very yellowy orange.
It will look red. White light is made up of a spectrum of many colours. The primary colours are red, green and blue. An object (in white light) appears yellow because it reflects red and green light but absorbs blue light. In red light, the same object will simply reflect the red light. Since there is no green light, the object will appear red. (A mixture of red and green gives yellow)
Why do you call it a "white object" ? Could it be because it looks white under white light ... light composed of every color ? Well then, the object must reflect every color. So it appears to be the color of whatever light you illuminate it with. Yellow under yellow light, etc.
In blue light, a yellow object would appear dark or black because yellow absorbs blue light and reflects other colors. This means that the object wouldn't reflect any of the blue light, making it appear dark.
white shoes appear white because it reflects all 7 colours of white light when fallen on to it.Therefore if only yellow light is fallen on to this object it would give out light rays which are yellow in colour . so shoes would appear yellow.
If the light is or contains the colour the object it is striking, then the object will appear to be the colour it originally is. If the light is not or does not contain the colour the object it is striking, then object will appear black. This is because an object will only reflect the light that is the same colour as it, all other light is absorbed. For example: Red, yellow, magenta, and white light will make a red object appear red as they all contain red light. Blue, green and cyan light will make a red object appear black.
It would look like a very, very, very, very yellowy orange.
It will look red. White light is made up of a spectrum of many colours. The primary colours are red, green and blue. An object (in white light) appears yellow because it reflects red and green light but absorbs blue light. In red light, the same object will simply reflect the red light. Since there is no green light, the object will appear red. (A mixture of red and green gives yellow)
Black
A yellow filter would absorb blue light, making a blue object appear black in a black-and-white photograph.
Why do you call it a "white object" ? Could it be because it looks white under white light ... light composed of every color ? Well then, the object must reflect every color. So it appears to be the color of whatever light you illuminate it with. Yellow under yellow light, etc.
A cyan object will appear black when only magenta light is shone on it. Cyan objects absorb magenta light, so no light is being reflected back to our eyes, causing the object to appear black.
A green object would appear dark or almost black under yellow light. This is because yellow light consists of wavelengths that are primarily in the yellow part of the spectrum, and it does not contain much green light. Therefore, the green object would not reflect much light back to our eyes, resulting in its dark appearance.
teal
Black