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Velocity decreases on a constant impulse, as impulse is equal to the change in momentum. When a force is applied for a certain amount of time, it results in a change in momentum which causes the velocity to decrease at a constant rate.

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If a constant force is applied for double the amount of time What happens to the impulse applied?

If a constant force is applied for double the amount of time, the impulse applied will also double. Impulse is equal to force multiplied by time, so if either the force or the time doubles, the impulse will also double.


What is the effect on the impulse if the force on ball a doubles while the time remains constant?

If the force on ball A doubles while the time remains constant, the impulse experienced by the ball will also double. Impulse is directly proportional to the force applied, so an increase in force will result in a proportional increase in impulse.


If the velocity is constant does that mean that there is no impulse?

Not necessarily. Impulse Fdt=change in momentum which could be written as mdv (constant mass, velocity changing) or dmv (changing mass, constant velocity - the so-called conveyor belt problem. Imagine a hopper filled with (say) coal is feeding the coal on to a conveyor belt. The mass of the belt increases with time, so a force has to be applied to it to keep it moving at constant velocity.


If the velocity is constant does that mean that the impulse is the momentum?

No, constant velocity means there is no change in velocity over time. Impulse is the change in momentum, given by the force applied over a period of time. Momentum is mass times velocity, a vector quantity.


What impulse occurs when the same force of 10 N acts on the cart for twice the time?

The impulse will be doubled. Impulse is the product of force and time, so doubling the time while keeping the force constant will result in a doubling of impulse.

Related Questions

Antonyms for impulse?

constant, restraint, dependability


When temperature of a gas decreases at constant volume it?

...pressure decreases.


When the temperature of a gas decreases a constant volume its?

...pressure decreases.


If demand decreases and supply is constant what happens to the equilibrium price?

If demand decreases and supply is constant, the price will increase.


If a constant force is applied for double the amount of time What happens to the impulse applied?

If a constant force is applied for double the amount of time, the impulse applied will also double. Impulse is equal to force multiplied by time, so if either the force or the time doubles, the impulse will also double.


What is the effect on the impulse if the force on ball a doubles while the time remains constant?

If the force on ball A doubles while the time remains constant, the impulse experienced by the ball will also double. Impulse is directly proportional to the force applied, so an increase in force will result in a proportional increase in impulse.


When the temperature of a gas at constant volume decreases it's?

...pressure decreases.


How can you find the value of the impulse?

The value of an impulse is the change in momentum. If the mass remains constant it is the mass times the change in velocity.


If the velocity is constant does that mean that there is no impulse?

Not necessarily. Impulse Fdt=change in momentum which could be written as mdv (constant mass, velocity changing) or dmv (changing mass, constant velocity - the so-called conveyor belt problem. Imagine a hopper filled with (say) coal is feeding the coal on to a conveyor belt. The mass of the belt increases with time, so a force has to be applied to it to keep it moving at constant velocity.


What happens to the rate constant as energy increases?

The rate constant decreases.


If the velocity is constant does that mean that the impulse is the momentum?

No, constant velocity means there is no change in velocity over time. Impulse is the change in momentum, given by the force applied over a period of time. Momentum is mass times velocity, a vector quantity.


What happens to the rate constant as activation energy increase?

The rate constant decreases.

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