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What does initial velocity squared plus 2 times acceleration times distance equal?
This equation represents the final velocity squared when an object is accelerating from an initial velocity over a certain distance. It is derived from the kinematic equation (v^2 = u^2 + 2as), where (v) is the final velocity, (u) is the initial velocity, (a) is the acceleration, and (s) is the distance traveled.
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If a car goes in 6.8 seconds how do you figure out the acceleration?
To calculate acceleration, you need to know the initial velocity of the car and its final velocity after 6.8 seconds. The acceleration can be found using the formula: acceleration = (final velocity - initial velocity) / time.
The box decelerates at a rate of 3 m s and skids 24 meters before coming to a stop How fast were you traveling when the box fell out?
To find the initial velocity of the box when it fell out, you can use the formula: final velocity squared = initial velocity squared + 2 * acceleration * distance. Given that the final velocity is 0 m/s, acceleration is 3 m/s^2, and distance is 24 meters, you can solve for the initial velocity.
How do you calculate the initial speed?
v2 = u2+ 2as where v squares is the final velocity , u squared is the initial velocity , a is the acceleration and s is the distance travelled. If it is free fall take a = 10m/s squared ( as gravity ).
What is the distance if the acceleration is 0.5 meters per sec square at 20 seconds?
The distance traveled can be calculated using the equation: distance = initial velocity * time + 0.5 * acceleration * time^2. If the acceleration is 0.5 m/s^2 and time is 20 seconds, we would need to know the initial velocity to determine the total distance traveled.
How does the unit of time enter twice in the unit of acceleration?
Acceleration is the rate of change of velocity over time. Since velocity is distance over time, acceleration becomes distance over time squared. This is why time enters twice in the unit of acceleration as distance per time squared.
How do you find displacement when you only have acceleration initial velocity and final velocity?
You can use the equation: Displacement = (final velocity squared - initial velocity squared) / (2 * acceleration). Plug in the values of final velocity, initial velocity, and acceleration to calculate the displacement.
If a car goes in 6.8 seconds how do you figure out the acceleration?
To calculate acceleration, you need to know the initial velocity of the car and its final velocity after 6.8 seconds. The acceleration can be found using the formula: acceleration = (final velocity - initial velocity) / time.
If you know the distance traveled and the time traveled can YOU determine an object and ACCELERATION?
no, you need to know its initial velocity to determine this; if initial velocity is zero then distance is 1/2 acceleration x time squared
How do you calculate tota distance traveled when given velocity time and acceleration?
Assuming constant acceleration: distance = v(0) t + (1/2) a t squared Where v(0) is the initial velocity.
The box decelerates at a rate of 3 m s and skids 24 meters before coming to a stop How fast were you traveling when the box fell out?
To find the initial velocity of the box when it fell out, you can use the formula: final velocity squared = initial velocity squared + 2 * acceleration * distance. Given that the final velocity is 0 m/s, acceleration is 3 m/s^2, and distance is 24 meters, you can solve for the initial velocity.
Why the second is squared in acceleration?
it is very simple........... velocity or speed = distance / time. acceleration = velocity / time but, we know that velocity = distance / time so just substitute the equation of velocity in acceleration...... so, finally we get , acceleration = distance/time*time so it is time squared.
How do you calculate the initial speed?
v2 = u2+ 2as where v squares is the final velocity , u squared is the initial velocity , a is the acceleration and s is the distance travelled. If it is free fall take a = 10m/s squared ( as gravity ).
What is the distance if the acceleration is 0.5 meters per sec square at 20 seconds?
The distance traveled can be calculated using the equation: distance = initial velocity * time + 0.5 * acceleration * time^2. If the acceleration is 0.5 m/s^2 and time is 20 seconds, we would need to know the initial velocity to determine the total distance traveled.
How does the unit of time enter twice in the unit of acceleration?
Acceleration is the rate of change of velocity over time. Since velocity is distance over time, acceleration becomes distance over time squared. This is why time enters twice in the unit of acceleration as distance per time squared.
How do you calculate velocity final with distance and acceleration?
aSsuming constant acceleration, and movement along a line, use the formula: vf2 = vi2 + (1/2)at2 (final speed squared equals initial speed squared plus one-half times acceleration times time squared).
State in words how acceleration is calculated?
There are two methods, it depends on what variables you have: 1. Subtract the initial velocity from the final velocity and divide that whole term by the time (Vf- Vi)/t = a 2. Square both the initial velocity and the final velocity and subtract the squared inital velocity from the squared final velocity and that answer by two times the distance (Vf^2 - Vi^2)/2d = a
How do you calculate the height an object reaches using only time and acceleration g?
Assuming (a) an initial velocity of zero, and (b) constant acceleration, the formula becomes: distance = 0.5 at2 (distance = 1/2 times acceleration times time squared).
