Gravity,contact force, friction, air resistance
Let's first imagine the man pushing on a car with the handbrake on. Obviously, the car does not move. The man is applying a force F (let us call it F1). The static friction of the brakes on the car are applying a force we shall call F2.Now, we know from Newton's laws that F = mass x acceleration (F = ma). The car is not accelerating, so F = 0. That is the net force of the man/car system is zero. So, F1 + F2 = 0, or if you prefer, F1 = -F2.In this case, the force of the man's feet on the ground cannot overcome the force of the brakes on the wheels. So the car does not move.Now, what happens if we release the handbrake? If enough force is applied to overcome the friction of the wheels and axles etc, the car will accelerate (a).The man's feet exert a force on the ground and the ground exerts an equal and opposite for on the man's feet. (Newton's 3rd law)The friction of the wheels exerts a force on the ground and the ground exerts an equal and opposite force on the wheels. (Newton's 3rd law)The man exerts a force on the car... and the car exerts an equal and opposite force on the man (3rd law)But, the force of the man's feet on the ground is greater than the opposing force of the wheel's friction on the ground. Therefore, there is a net force and the "man + car" system accelerates. Note that Newton's 3rd law applies to each pair of objects (car/ground), (car/man), (man/ground) seperately.
The equal and opposite force to the downward force of gravity pulling on a man standing on the beach is the normal force exerted by the ground pushing back up on the man. This normal force prevents the man from sinking into the ground due to the force of gravity.
B. A force equal to his weight. When a man is walking horizontally on a level surface, the force he applies to the ground is equal in magnitude to his weight in order to support his body and propel him forward.
when a man is standing on ground all his weight is in downward direction and pressure is the force divided by area as force is maximum and area is minimum so pressure will be more when he is standing
No work is done on the man himself as he walks, as work is defined as force applied over a distance in the direction of the force. The man is the one exerting a force to overcome friction against the ground, causing him to move forward. Therefore, work is done by the man to move himself.
Let's first imagine the man pushing on a car with the handbrake on. Obviously, the car does not move. The man is applying a force F (let us call it F1). The static friction of the brakes on the car are applying a force we shall call F2.Now, we know from Newton's laws that F = mass x acceleration (F = ma). The car is not accelerating, so F = 0. That is the net force of the man/car system is zero. So, F1 + F2 = 0, or if you prefer, F1 = -F2.In this case, the force of the man's feet on the ground cannot overcome the force of the brakes on the wheels. So the car does not move.Now, what happens if we release the handbrake? If enough force is applied to overcome the friction of the wheels and axles etc, the car will accelerate (a).The man's feet exert a force on the ground and the ground exerts an equal and opposite for on the man's feet. (Newton's 3rd law)The friction of the wheels exerts a force on the ground and the ground exerts an equal and opposite force on the wheels. (Newton's 3rd law)The man exerts a force on the car... and the car exerts an equal and opposite force on the man (3rd law)But, the force of the man's feet on the ground is greater than the opposing force of the wheel's friction on the ground. Therefore, there is a net force and the "man + car" system accelerates. Note that Newton's 3rd law applies to each pair of objects (car/ground), (car/man), (man/ground) seperately.
The equal and opposite force to the downward force of gravity pulling on a man standing on the beach is the normal force exerted by the ground pushing back up on the man. This normal force prevents the man from sinking into the ground due to the force of gravity.
When we walk on the ground our foot pushes the ground backward, and in return, the ground pushes our foot forward. The forward reaction exerted by the ground pushes our foot forward. The forward reaction exerted by the ground on our foot makes us walk forward.
When a man stands on the ground his weight (force) is spread over a small area, causing high pressure on the ground (pressure is force divided by area). When a man lies on the ground his same weight (force) is spread over a larger area, causing low pressure on the ground (pressure is force divided by area).
The British were told to walk across no man's land during WW1 because of the rough ground. Walking was safer than running along the ground.
B. A force equal to his weight. When a man is walking horizontally on a level surface, the force he applies to the ground is equal in magnitude to his weight in order to support his body and propel him forward.
when a man is standing on ground all his weight is in downward direction and pressure is the force divided by area as force is maximum and area is minimum so pressure will be more when he is standing
There is more pressure when the man is standing, since pressure is the amount of force acting on a certain area and is calculated by dividing the force by the area. When a man is standing, the area of contact with the ground is less than the area of contact when lying down. Since his weight is constant, there is more pressure when he is standing.
No work is done on the man himself as he walks, as work is defined as force applied over a distance in the direction of the force. The man is the one exerting a force to overcome friction against the ground, causing him to move forward. Therefore, work is done by the man to move himself.
The man said he did not want to walk.
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a man who can not walk is a legless man or women