The force acting on a book on a slope is composed of its weight acting straight downward and a component of gravity pulling the book down the slope. The normal force from the slope acts perpendicular to the slope to prevent the book from sinking into it. Frictional force also opposes the book's motion down the slope.
The normal force exerted by the book on the board is equal in magnitude but opposite in direction to the component of the book's weight perpendicular to the slope of the board. In this case, the normal force will be equal to the weight of the book times the cosine of the angle of the slope, in this case, 60 degrees. So the normal force will be equal to (2.0 kg * 9.8 m/s^2) * cos(60 degrees).
Not quite sure I understand the rather vague question. But gravity ensures the book remains stationary on the level tabletop. If the table is tilted enough, the book will slide down the slope, still governed by gravity. If I gave the book a shove and it slid off the level tabletop, I would be using a physical force.
The normal force on a slope helps keep an object stable by counteracting the force of gravity pulling it downhill. The greater the normal force, the more stable the object will be on the slope.
The force that pulls material down a slope is gravity. Gravity acts to pull objects towards the center of the Earth, causing them to move downwards along the slope due to the force of gravity. Friction between the material and the slope also plays a role in determining how quickly the material moves down the slope.
The force acting on the ball as it moves down the slope is the gravitational force, which pulls the ball downward towards the center of the Earth. Additionally, there may be a component of the force due to friction between the ball and the surface of the slope, which opposes the motion of the ball.
The normal force exerted by the book on the board is equal in magnitude but opposite in direction to the component of the book's weight perpendicular to the slope of the board. In this case, the normal force will be equal to the weight of the book times the cosine of the angle of the slope, in this case, 60 degrees. So the normal force will be equal to (2.0 kg * 9.8 m/s^2) * cos(60 degrees).
Not quite sure I understand the rather vague question. But gravity ensures the book remains stationary on the level tabletop. If the table is tilted enough, the book will slide down the slope, still governed by gravity. If I gave the book a shove and it slid off the level tabletop, I would be using a physical force.
The normal force on a slope helps keep an object stable by counteracting the force of gravity pulling it downhill. The greater the normal force, the more stable the object will be on the slope.
The slope of a force vs. time graph is equal to the change in momentum or the Impulse.
Parallel to the surface of the slope and opposite to the movement of an object on the slope. Parallel to the surface of the slope and up-slope, in the case of an object resting in place on the slope.
The force that pulls material down a slope is gravity. Gravity acts to pull objects towards the center of the Earth, causing them to move downwards along the slope due to the force of gravity. Friction between the material and the slope also plays a role in determining how quickly the material moves down the slope.
The force acting on the ball as it moves down the slope is the gravitational force, which pulls the ball downward towards the center of the Earth. Additionally, there may be a component of the force due to friction between the ball and the surface of the slope, which opposes the motion of the ball.
Gravity is the force that makes the car move faster down the slope. As the car descends, gravity pulls it downhill, increasing its speed. The steeper the slope, the greater the acceleration due to gravity.
The slope of the graph represents the shear force at a particular point on a beam. As the load position changes along the beam, the magnitude of the shear force and therefore the slope of the graph varies accordingly. The slope will be steeper where the shear force is greater, such as under concentrated loads or at support points.
Gravity.
book = 1kg, then force down slope = 1*sin 30 = 0.5 kg force of book on surface = 1*cos 30 = 0.866kg 0.5/0.866 = 0.577
the normal force is acting on the sled-- it's what keeps the sled from falling through the slope