The current is doubled.
I = V/R
I=2V/R
Lets assign arbitrary numbers to voltage and resistance to evaluate what happens. Voltage will be 8 volts and resistance will be 2 ohms.
I = 8/2 Therefore current = 4amps
If voltage is doubled then,
I =2(8)/2
I=16/2
I = 8 amps
According to ohm's law,
V=IR
where V is voltage, I is current and R is resistance. In ur question, I assume that R remains constant so wen V is doubled, it becomes 2V,
the current doubles too,
2V=2I. R
There, curent doubles.
Ohm's Law: Voltage is Current Times Resistance
If you double the current while holding the resistance constant, then that means you had to also double the voltage. Since power is voltage times current, that means that you quadrupled the power.
When voltage is doubled it would lead to a current that was also doubled. This is true only in a perfect model where all other factors, like resistance, are equal. This is due to Ohm's law.
Power is quadrupled, because power = voltage x current.
The current will double.
raises amperage
icrease 2 times
Voltage x current = power (watts)
In DC, power equals voltage x current. In AC, power equals voltage x current x power factor. The power factor is an adimensional constant, and in common circuits it is often close to 1.
current=watts(power)/voltage
Yes, power is directly proportional to current. Power is equal to amps times volts, and as current goes up (with voltage remaining constant), power will go up. Double current, and you'll double power. Cut current in half, and you'll cut power in half. (Voltage stays the same in all this).
P=IV Power=current x voltage
The heat released by the rheostat with double the voltage will quadruple. When voltage is tripled, the power loss is 32 or 9 times that before. A rheostat is a kind of variable resistor. Since E = IR (voltage equals current times resistance), then I = E/R (current equals voltage divided by resistance). If the voltage is doubled and the resistance stays the same, then--you can see by the formula--the current would double. Now, power dissipated by a resistor is related to the product of the current and voltage (P = IE). But since a doubling of voltage produces also a doubling of current, double the current results in 2X2=4 times the power (heat) loss.
Power = (current) times (voltage)Current = (Power) divided by (voltage)Voltage = (Power) divided by (current)
The unit of power is watts, the unit of current is amps, and the unit of voltage it volts. Power = Voltage X Current Voltage = Power / Current Current = Power / Voltage In electricity, power is symbolized with a P, current with an I, and voltage with a V. The real formula looks like: P = V x I V = P / I I = P / V
You do not need ohm's law to relate power to current and voltage. Power is current times voltage. If you know current and voltage, you do not need to know resistance.
Voltage x current = power (watts)
You get power, which is voltage * current (so both!).
P = I^2 R = IV = v^2 / R , Where P is power, I is current, R is resistance, and V is voltage. Given voltage and current, power = current * voltage, or P = IV.
in ac circuits power,P=VICOS@ @ is the angle between voltage and current. in dc P=VI V is the voltage I is the current. Power (in Watts) is current (A) x voltage (V)
If the resistance is 1.2k and the current is 0.024 ma, then the voltage is 0.0288 volts. (Voltage = resistance times current) If the voltage is 0.0288V and the current is 0.024 ma, then the power is 0.6912 microwatts. (Power = voltage times current)
If there is no current, there is no power.The voltage can be measured with a voltmeter.
Power is contituted by both current and voltage So we consume both current and voltage
current is the other factor. power (wattage) is the product of current (amps) and voltage