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What is the apparent weight for a body floating in water equal to?
The apparent weight of a body floating in water is equal to the weight of the water displaced by the body. This is known as Archimedes' principle. The apparent weight is less than the actual weight of the body due to the buoyant force acting on it.
The volume of the displaced water is equal to the volume of the portion of the object that's above the surface of the water?
This statement is not correct. The weight of the water displaced by a body in it, is equal to the buoyancy force that the body will experience. In the case the body floats on the surface of water, the weight of the water displaced by the body is equal to the weight of the body.
What is the relation do you find between the weight of the floating body and the weight of water that is displaced?
The weight of the floating body is equal to the weight of the water that is displaced. This relationship is known as Archimedes' principle. The buoyant force acting on the floating body is equal to the weight of the water it displaces, allowing the body to float.
What happen when weight of body on water equal to lifting force of water?
When the weight of the body is equal to the lifting force of water (buoyant force), the body will be in equilibrium and float at a specific level in the water. This is known as the Archimedes' principle. The buoyant force acting upwards is equal to the weight of the water displaced by the body, allowing it to stay afloat.
How is the weight of water displaced by a floating body related to the weight of the body itself?
The weight of water displaced by a floating body is equal to the weight of the body itself. This is known as Archimedes' principle, which states that the buoyant force acting on a body immersed in fluid is equal to the weight of the fluid displaced by the body.
What is the apparent weight for a body floating in water equal to?
The apparent weight of a body floating in water is equal to the weight of the water displaced by the body. This is known as Archimedes' principle. The apparent weight is less than the actual weight of the body due to the buoyant force acting on it.
The volume of the displaced water is equal to the volume of the portion of the object that's above the surface of the water?
This statement is not correct. The weight of the water displaced by a body in it, is equal to the buoyancy force that the body will experience. In the case the body floats on the surface of water, the weight of the water displaced by the body is equal to the weight of the body.
What is the relation do you find between the weight of the floating body and the weight of water that is displaced?
The weight of the floating body is equal to the weight of the water that is displaced. This relationship is known as Archimedes' principle. The buoyant force acting on the floating body is equal to the weight of the water it displaces, allowing the body to float.
What happen when weight of body on water equal to lifting force of water?
When the weight of the body is equal to the lifting force of water (buoyant force), the body will be in equilibrium and float at a specific level in the water. This is known as the Archimedes' principle. The buoyant force acting upwards is equal to the weight of the water displaced by the body, allowing it to stay afloat.
How is the weight of water displaced by a floating body related to the weight of the body itself?
The weight of water displaced by a floating body is equal to the weight of the body itself. This is known as Archimedes' principle, which states that the buoyant force acting on a body immersed in fluid is equal to the weight of the fluid displaced by the body.
Who discovered that the Weight of a body in water is equal to the volume of water displaced?
Greek scholar Archimedes
What is happening if the weight of the body in the water becomes zero?
If the weight of a body in water becomes zero, it means that the buoyant force acting on the body is equal to the weight of the body. This implies that the body is completely submerged and in equilibrium, neither sinking nor rising.
How much will a body of weight 35N weigh in water if it displaces 1 liter of water?
The weight of an object in water is equal to the weight of the object in air minus the weight of the water it displaces. The weight of the object in air is 35N. To calculate the weight of the water displaced, we need to convert 1 liter of water to kilograms (1 liter of water is approximately 1 kg). Therefore, the weight of the body in water would be 35N - 1kg x 9.81 m/s^2 ≈ 25.19N.
Why and how does a body lose weight when it is immersed in water?
When a body is immersed in water, it experiences buoyant force which reduces its weight. This results in a decrease in apparent weight, which can be misinterpreted as weight loss. However, the actual mass of the body remains the same as the buoyant force only affects the apparent weight.
Why do you seem to weigh more in in than water?
The density of the human body is greater than that of water. This means that when you step into water, the water you displace has a weight equal to your weight. If you weigh more than the weight of the water that you displace, you will sink.
How is your weight affected in the water?
Your weight is reduced. If your body floats and you cannot make it sink, you are weightless (a scale put under you will not register any weight) and the weight of the water you displace will equal your land weight. If you can make yourself bouyant (neither sinking nor floating) then you are also weightless, and your land weight is the same as your body's volume of water. If you can make yourself sink by exhaling and allowing your body to hold itself still at the bottom of the pool) your weight at the bottom of the pool will be equal to your land weight minus the weight of the water you displace (the amount of water in your body's volume). If you float, your body is less dense than the water you are in. If you are bouyant, the density of your body equals the density (specific gravity) of the water, and if you sink, you are more dense than the water (specific gravity) you are in. why do you wanna know r u fat?
Calculate the upthrust on a body which weighs 100N in air and appears to weigh 70N in H20.?
The upthrust on a body in water is equal to the weight of the water displaced by the body. Since the weight of the body decreases by 30N (100N - 70N) in water, the upthrust is also 30N.
