When the incident ray is at an angle of 90 degrees to the prism, it will not enter the prism but will reflect off of it. This occurs because the light undergoes total internal reflection at the interface between the two mediums due to the critical angle being reached.
The angle between the incident ray and the reflected ray is equal to the angle between the incident ray and the normal. When the mirror is rotated, the normal also rotates by the same angle. Therefore, the angle between the incident ray and the reflected ray will still be 20 degrees.
The incident angle to the Mirror will be 10 deG.
You have given the glancing angle as 30 degree. So the angle of incidence = 90-30 = 60 deg As i = r by the law of reflection the angle of reflection = 60 deg
Very interesting query! Usually it is always possible to retrace the path of light. Suppose a light incident at angle 30 deg in rarer medium ie air it would go with an angle 19.5 deg in a glass medium whose refractive index is 1.5. Now if light traversing form glass incidents at an angle 19.5 deg then it would go refracted with angle of refraction 30 deg. If this is true then in case of ray traversing from denser into rarer at an angle of incidence equal to critical angle, the ray would go along the boundary as the angle of refraction becomes 90 deg. So if we retrace the ray going along the boundary of the two medium then the ray would bend into the denser medium making an angle equal to the value of critical angle with the normal drawn to the boundary line.
When a light wave traveling through air strikes a boundary with water at a 45° angle, it will change speed and direction due to a change in the medium's refractive index. This phenomenon is called refraction. The angle of refraction depends on the refractive indices of air and water according to Snell's law.
The angle between the incident ray and the reflected ray is equal to the angle between the incident ray and the normal. When the mirror is rotated, the normal also rotates by the same angle. Therefore, the angle between the incident ray and the reflected ray will still be 20 degrees.
The incident angle to the Mirror will be 10 deG.
80/2 = 40 deg
The angle between the incident ray and reflected ray is known as angle of deviation due to reflection. This will always be equal to 2i. Here i is the angle of incidence. So if 2i = 90 then i = 90/2 = 45 So the angle of incidence has to be 45 deg
The first angle is 166 deg and the second is 14 deg.
You have given the glancing angle as 30 degree. So the angle of incidence = 90-30 = 60 deg As i = r by the law of reflection the angle of reflection = 60 deg
The bases of a prism are general polygons and can have any angles in the range (0, 360) degrees excluding 180 deg, subject only to constraints imposed by the polygon. The lateral faces are all rectangles (in a right prism) and they meet the bases at right angles.
the supplementary angle of 22 deg = 180-22 = 158 deg.
180 deg - 165 deg 12 min
Not sure whether the o after the 16 is a typo for 0 or an attempted degree symbol. The supplement of an angle is 180 - the angle. So, if it was 16 deg, the supplement is 164 deg and if it was 160 deg, the supplement is 20 deg.
An Obtuse angle is greater than 90 deg; an Acute angle is less then 90 deg.
the angle at a point is 0 deg.