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The horizontal force required would be equal to the mass of the puck multiplied by the acceleration due to gravity (1 kg * 9.81 m/s^2 = 9.81 N). This force is needed to overcome the gravitational force acting downward on the puck.

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1y ago

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What is the horizontal force that must be applied to produce an acceleration of 1.8 g for a 1.2 kg puck -on a horizontal friction free air table?

The horizontal force required to produce an acceleration of 1.8 g on a 1.2 kg puck is 21.6 N. This is calculated by multiplying the mass of the puck by the acceleration due to gravity (1.8 g = 1.8 x 9.81 m/s^2) to get the force needed.


How do you calculate the horizontal force that must be applied to produce an acceleration of 1.8 g?

F = M A F = force M = mass of the object being forced A = the object's acceleration You want A = 1.8 G = 1.8 x 9.8 = 17.64 meters per second2 Fnewtons = (17.64) x (Mkilograms)


What will the mass and acceleration produce if the applied force is constant?

If the applied force is constant, the acceleration will also be constant. To know the actual amount of acceleration, you divide the force by the mass.


When acceleration is increased what happens to force?

it increases in direct proportion to the force applied


How is force related acceleration?

Force is directly proportional to acceleration, meaning that the greater the force applied to an object, the greater its acceleration will be. This is described by Newton's second law: F = ma, where F is the force applied to an object, m is the mass of the object, and a is the acceleration of the object.


What is the horizontal force that must be applied to produce an acceration of 2.8 g for 1.2 kg puck on a horizontal friction free air table?

Where the question says "2.8 g", we understand that to mean2.8 times the acceleration of gravity = 27.44 m/sec2 .F = M A = (1.2 kg) x (27.44 m/s2) = 32.928 newtons


What happens to the acceleration as you increase the mass?

As per Newton's first law of motion, if the applied force remains the same, an increase in mass will result in a decrease in acceleration. In contrast, if the acceleration were to remain the same when the mass increases, there must be a greater force applied.


When you apply a tiny force to a tiny object or a large force to a large object you produce?

When you apply a force to a mass you produce acceleration. "Tiny" and "large" are not well defined here, but the basic equation is F = ma, so if the forces are proportional to the masses in each case (for example, a 0.1 N force applied to a 0.1 g object and a 1000 N force applied to a 1000 g object) then you will produce the same acceleration for both objects.


What must act on a system in order to produce an acceleration?

A net external force must act on the system in order to produce an acceleration, according to Newton's second law of motion. This force can come from various sources, such as gravity, friction, or applied forces.


What type of motion would produce positive acceleration in an object?

Positive acceleration in an object can be produced by a force applied in the direction of its motion. This force will cause the object to increase its speed over time.


The law applied force states that a body's change in mass is proportional to the amount of force applied to it?

There is no such law. Newton's Second Law states that: force = mass x acceleration So, more force will produce more acceleration. More mass will result in less acceleration. However, the mass of a body usually doesn't change - but you can use this law to compare the same force applied to different objects, of a different mass.


What does newtons 2nd law state?

Newtons 2nd law means that when force is applied on any object an acceleration is produced in the direction of force which is applied on it. The acceleration produced in the object is directly proportional to the force applied on the object i.e. if force increases then acceleration will also increase and the acceleration is inversely proportional to the mass of object i.e. if the mass of the body decreases then acceleration will increase. If force is represented by 'F', acceleration by 'a' and mass by 'm' then a is directly proportional to F a is inversely proportional to m