The vertical distance covered by a free falling object is given by the formula: S= ut+0.5at^2, where S is the distance covered (height of the building), u is the initial velocity (for this case it is 0 since the body is released from rest), t is the time taken for the object to hit the ground (it has taken 5 seconds) and a is the acceleration due to gravitational pull (assumed to be 9.8ms^2). Therefore, the height of the building is given by (0x5 +0.5x9.8 x25) which is 122.5m.
The speed of the ball when it reaches the ground can be calculated using the formula: speed = acceleration due to gravity x time taken. Given that the acceleration due to gravity is approximately 9.81 m/s^2, multiplying it by the time taken (4.5 seconds) gives a speed of approximately 44.145 m/s.
The velocity of the rock as it reaches the ground after 3.5 seconds of free fall can be calculated using the equation v = gt, where v is the final velocity, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time in seconds. Substituting the values, v = 9.81 m/s^2 * 3.5 s = 34.335 m/s. So, the velocity of the rock as it reaches the ground is approximately 34.34 m/s.
The speed of the ball when it reaches the ground can be calculated using the kinematic equation: v = u + gt, where v is the final velocity (speed), u is the initial velocity (0 m/s as it's dropped), g is acceleration due to gravity (9.8 m/s^2), and t is the time taken (5.5 s in this case). Plugging in the values, v = 0 + 9.8 * 5.5 = 53.9 m/s. So, the speed of the ball when it reaches the ground would be approximately 53.9 m/s.
When an object is dropped, it falls towards the ground due to the force of gravity acting on it. The object accelerates as it falls until it reaches the ground or another surface, where it comes to a stop.
The height of the building can be calculated using the formula: h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity (9.8 m/s^2), and t is the time taken to reach the ground (1.0 seconds in this case). Substituting the values, we get h = (1/2)(9.8)(1.0)^2 = 4.9 meters. Therefore, the height of the building is 4.9 meters.
a. 144 feet b. 96 ft/sec.
The speed of the ball when it reaches the ground can be calculated using the formula: speed = acceleration due to gravity x time taken. Given that the acceleration due to gravity is approximately 9.81 m/s^2, multiplying it by the time taken (4.5 seconds) gives a speed of approximately 44.145 m/s.
There is no reason for the object to change.
5 m
The velocity of the rock as it reaches the ground after 3.5 seconds of free fall can be calculated using the equation v = gt, where v is the final velocity, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time in seconds. Substituting the values, v = 9.81 m/s^2 * 3.5 s = 34.335 m/s. So, the velocity of the rock as it reaches the ground is approximately 34.34 m/s.
381 metres
When an object is dropped, it falls towards the ground due to the force of gravity acting on it. The object accelerates as it falls until it reaches the ground or another surface, where it comes to a stop.
The speed of the ball when it reaches the ground can be calculated using the kinematic equation: v = u + gt, where v is the final velocity (speed), u is the initial velocity (0 m/s as it's dropped), g is acceleration due to gravity (9.8 m/s^2), and t is the time taken (5.5 s in this case). Plugging in the values, v = 0 + 9.8 * 5.5 = 53.9 m/s. So, the speed of the ball when it reaches the ground would be approximately 53.9 m/s.
44 meters tall
176.4 meters
The height of the building can be calculated using the formula: h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity (9.8 m/s^2), and t is the time taken to reach the ground (1.0 seconds in this case). Substituting the values, we get h = (1/2)(9.8)(1.0)^2 = 4.9 meters. Therefore, the height of the building is 4.9 meters.
Ignoring air resistance . . .H = 1/2 G t2t = sqrt(2H/G) = sqrt(2 x 363 / 32.2) = 4.75 seconds (rounded)