answersLogoWhite

0

The vertical distance covered by a free falling object is given by the formula: S= ut+0.5at^2, where S is the distance covered (height of the building), u is the initial velocity (for this case it is 0 since the body is released from rest), t is the time taken for the object to hit the ground (it has taken 5 seconds) and a is the acceleration due to gravitational pull (assumed to be 9.8ms^2). Therefore, the height of the building is given by (0x5 +0.5x9.8 x25) which is 122.5m.

User Avatar

Wiki User

10y ago

What else can I help you with?

Continue Learning about Physics

What is the speed of a ball that has dropped from a 100 m tall building when it reaches the ground in 4.5 seconds?

The speed of the ball when it reaches the ground can be calculated using the formula: speed = acceleration due to gravity x time taken. Given that the acceleration due to gravity is approximately 9.81 m/s^2, multiplying it by the time taken (4.5 seconds) gives a speed of approximately 44.145 m/s.


A rock is dropped from a height of 60 m and is in free fall. What is the velocity of the rock as it reaches the ground 3.5 seconds later?

The velocity of the rock as it reaches the ground after 3.5 seconds of free fall can be calculated using the equation v = gt, where v is the final velocity, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time in seconds. Substituting the values, v = 9.81 m/s^2 * 3.5 s = 34.335 m/s. So, the velocity of the rock as it reaches the ground is approximately 34.34 m/s.


A ball is dropped from a 150-m tall building Neglecting air resistance what will the speed of the ball be when it reaches the ground 5.5 seconds later Apex?

The speed of the ball when it reaches the ground can be calculated using the kinematic equation: v = u + gt, where v is the final velocity (speed), u is the initial velocity (0 m/s as it's dropped), g is acceleration due to gravity (9.8 m/s^2), and t is the time taken (5.5 s in this case). Plugging in the values, v = 0 + 9.8 * 5.5 = 53.9 m/s. So, the speed of the ball when it reaches the ground would be approximately 53.9 m/s.


What happens when an object is dropped?

When an object is dropped, it falls towards the ground due to the force of gravity acting on it. The object accelerates as it falls until it reaches the ground or another surface, where it comes to a stop.


What If a ball is dropped from the top of a building and it hits the ground 1.0 seconds later.how high is the building?

The height of the building can be calculated using the formula: h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity (9.8 m/s^2), and t is the time taken to reach the ground (1.0 seconds in this case). Substituting the values, we get h = (1/2)(9.8)(1.0)^2 = 4.9 meters. Therefore, the height of the building is 4.9 meters.

Related Questions

A ball is dropped from the top of a building and hits the ground 3 seconds later. a. what is the height if the building b. with what speed did it hit the ground?

a. 144 feet b. 96 ft/sec.


What is the speed of a ball that has dropped from a 100 m tall building when it reaches the ground in 4.5 seconds?

The speed of the ball when it reaches the ground can be calculated using the formula: speed = acceleration due to gravity x time taken. Given that the acceleration due to gravity is approximately 9.81 m/s^2, multiplying it by the time taken (4.5 seconds) gives a speed of approximately 44.145 m/s.


What would be the change for a 10 gram object dropped from a 20 meter building if it takes 2 seconds to reach the ground?

There is no reason for the object to change.


A 5-kg flower-vase accidentally falls from the balcony of a high building reaches a pile of sand on the ground in 3 seconds?

5 m


A rock is dropped from a height of 60 m and is in free fall. What is the velocity of the rock as it reaches the ground 3.5 seconds later?

The velocity of the rock as it reaches the ground after 3.5 seconds of free fall can be calculated using the equation v = gt, where v is the final velocity, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time in seconds. Substituting the values, v = 9.81 m/s^2 * 3.5 s = 34.335 m/s. So, the velocity of the rock as it reaches the ground is approximately 34.34 m/s.


A ball was dropped on a top of the building and hits the ground after 15 s. What is the height of the building?

381 metres


What happens when an object is dropped?

When an object is dropped, it falls towards the ground due to the force of gravity acting on it. The object accelerates as it falls until it reaches the ground or another surface, where it comes to a stop.


A ball is dropped from a 150-m tall building Neglecting air resistance what will the speed of the ball be when it reaches the ground 5.5 seconds later Apex?

The speed of the ball when it reaches the ground can be calculated using the kinematic equation: v = u + gt, where v is the final velocity (speed), u is the initial velocity (0 m/s as it's dropped), g is acceleration due to gravity (9.8 m/s^2), and t is the time taken (5.5 s in this case). Plugging in the values, v = 0 + 9.8 * 5.5 = 53.9 m/s. So, the speed of the ball when it reaches the ground would be approximately 53.9 m/s.


If an object is dropped from a tall building and hits the ground 3.0 sec later how tall is the building?

44 meters tall


A rock is dropped from a cliff and hits the ground 6.0 seconds later How high is the cliff?

176.4 meters


What If a ball is dropped from the top of a building and it hits the ground 1.0 seconds later.how high is the building?

The height of the building can be calculated using the formula: h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity (9.8 m/s^2), and t is the time taken to reach the ground (1.0 seconds in this case). Substituting the values, we get h = (1/2)(9.8)(1.0)^2 = 4.9 meters. Therefore, the height of the building is 4.9 meters.


How many seconds will it take for an egg dropped from the top of a 363 foot tall building to hit the ground?

Ignoring air resistance . . .H = 1/2 G t2t = sqrt(2H/G) = sqrt(2 x 363 / 32.2) = 4.75 seconds (rounded)