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If a system requires 150j on input work and produces 123j of output work what is the efficiency?
The efficiency of the system would be calculated as the ratio of output work to input work, multiplied by 100% to express it as a percentage. In this case, the efficiency would be 82% (123j output work / 150j input work) * 100%.
How efficient is a machine that outputs 67J when 150J of work are input?
The efficiency of the machine can be calculated using the formula efficiency = (useful output / total input) * 100%. In this case, the efficiency of the machine would be (67J / 150J) * 100% = 44.7%. This means that the machine is operating at 44.7% efficiency in converting input work to useful output.
What is the power of a cyclist when she overcomes a resistive force of 30N in order to cycle 30m. It takes her 6 seconds to cycle this distance.?
The work done against the resistive force is 30N * 30m = 900 J. Since work is done in 6 seconds, the power exerted by the cyclist is 900 J / 6 s = 150 Watts.
A force of 100 N was necessary to lift a tree. A total of 150 Joules of work was done. How far was the tree lifted?
To find the distance the tree was lifted, we can use the formula for work: Work = Force x Distance. Given that 150 Joules of work was done and the force was 100 N, we can rearrange the formula as Distance = Work / Force. Plugging in the values, we get Distance = 150J / 100N = 1.5 meters. Therefore, the tree was lifted 1.5 meters.
If the potential energy of a swing is 200 J at its highest point and 50 J at its lowest point what is the kinetic energy of the swing at its lowest point if mechanical energy is conserved?
150J, as the potential energy has been converted to kinetic energy as the swing accelerates downwards (and forwards) from the top of its swing. Therefore the decrease in potential energy corresponds directly to the increase in kinetic energy if we are ignoring things like friction. So KE = 200-50= 150
If a system requires 150j on input work and produces 123j of output work what is the efficiency?
The efficiency of the system would be calculated as the ratio of output work to input work, multiplied by 100% to express it as a percentage. In this case, the efficiency would be 82% (123j output work / 150j input work) * 100%.
How efficient is a machine that outputs 67J when 150J of work are input?
The efficiency of the machine can be calculated using the formula efficiency = (useful output / total input) * 100%. In this case, the efficiency of the machine would be (67J / 150J) * 100% = 44.7%. This means that the machine is operating at 44.7% efficiency in converting input work to useful output.
What is the difference between a Cessna 150 and a Cessna 150J?
Two different versions of the same airplane. There were several earlier versions of the aircraft, each with slight improvements or changes from the original. The 'J' model introduced a key operated electric starter, along with rocker type electrical switches to replace the older style "toggle" switches
What is the power of a cyclist when she overcomes a resistive force of 30N in order to cycle 30m. It takes her 6 seconds to cycle this distance.?
The work done against the resistive force is 30N * 30m = 900 J. Since work is done in 6 seconds, the power exerted by the cyclist is 900 J / 6 s = 150 Watts.
A force of 100 N was necessary to lift a tree. A total of 150 Joules of work was done. How far was the tree lifted?
To find the distance the tree was lifted, we can use the formula for work: Work = Force x Distance. Given that 150 Joules of work was done and the force was 100 N, we can rearrange the formula as Distance = Work / Force. Plugging in the values, we get Distance = 150J / 100N = 1.5 meters. Therefore, the tree was lifted 1.5 meters.
What is the output voltage of a defibrillator?
It depends! The older Monophasic (one shock per shock -one way) machines can use as much as 5000V. The newer Biphasic (two shocks per shock -back and forth) machines use around 2200V. Less energy= less heart damage risk. Now to some details: The energy output of these machines is termed in Joules. Usually something like 150J for a Biphasic or 200J in a Mono as a first shock. The critical part is that Joules are a product of the Voltage * Amperage * time (1 sec). Therefore in the above examples : 1500V * 0.1A * 1sec = 150J 2000V * 0.1A * 1 sec= 200J The high voltage is generated by converting either the mains power or the internal battery power to the required voltage via an inverter and then stored in a capacitor for rapid release when needed. As an example, cars usually run on a 12V system, BUT the energy sent to the spark plug from the ignition coil is massive and dangerous for a very short time, as is the energy during defibrillation. So, don't think your gloves will save you. Don't touch the patient when shocking them -as in don't continue compressions when shocking them. There is no such thing as an energy rated safe disposable medical glove. Hope this helps.
Can you replace a Cont 0-200 with a Lycoming 0-235 on a Cessna 150J would there be any problems advantages or disadvantages with this change overall?
the cont 0-200 has a better fuel consumption rate. Check with your IA and he can tell you if that particular combination is an approved installation It is an approved installation; an Airframe and Powerplant shop files a Supplemental Type Certificate, the FAA signs off on it (the O-235 was used in the Cessna 152 so there's no real problem with the conversion) and the mechanic inserts the new engine in your classic airplane. One quick note: Lycoming is not shy about pricing its parts.
If the potential energy of a swing is 200 J at its highest point and 50 J at its lowest point what is the kinetic energy of the swing at its lowest point if mechanical energy is conserved?
150J, as the potential energy has been converted to kinetic energy as the swing accelerates downwards (and forwards) from the top of its swing. Therefore the decrease in potential energy corresponds directly to the increase in kinetic energy if we are ignoring things like friction. So KE = 200-50= 150
What is the change in the internal energy of the gas if 500 cal of heat are added to a gas and the gas expands doing 500J of work?
The change in internal energy is 205 cal. The change in internal energy (ΔU) is given by the formula ΔU = Q - W, where Q is the heat added (500 cal) and W is the work done by the gas (500 J = 119.6 cal). Therefore, ΔU = 500 cal - 119.6 cal = 380.4 cal.
