1r is not a standard mathematical notation. It may be a variable or placeholder used in a specific context. Without more information, it is unclear what 1r represents.
Tangential acceleration is d/dr mcV = mc dVcdt = mdv/dt. The tangential acceleration is dV/dt is produced from the Vector Energy (mcV, the "Dark Energy"). Newton "added" the tangential acceleration as " dV/dt" to balance he Gradient acceleration v2/r 1R.
The force is the derivative of the energy W = -Ze2zc/4pir + cP = -vh/w + cP where v=alphaZ c, and Z is the product of the charges in electron and Alpha is the Fine Structure Constant and c is the speed of light. The Energy W has potential enrgy vh/w and the vector Momentum energy cP. This Momentum energy is the so-called "Dark Energy" and accounts for the Momentum energy. cmV=cP. This Momentum energy exists when there is motion of the electron, mV, then there is vector energy cP. The force is F= XW = [d/dr, DEL] [-vh/w, cP] = [vp/r -cDEl.P, cdP/dr - DEL vh/w + cDElxP] F = [vp/r -cp/r cos(P), -cp/r 1P + vp/r 1R + cp/r sin(P) 1RxP] F = cp/r[v/c -cos(P) , -1P + v/c 1R + sin(P) 1RxP], cp/r = cp/ct=p/t = mv/t = ma. The energy is W = -vh/w + cP where cP is the momentum energy between the charges of electron.
Force is the first derivative of energy. The gravitation energy is W = -mGm/r + cmV = -mvh/r + cP Gravity energy is a Quaternion energy consisting of a scalar force -mGM/r and a vector energy cmV = cP a momentum vector energy, the so-called Dark Energy. In addition physics does not recognize the four space derivative X,properly a Quaternion derivative, X =[d/dr, DEL]. With these reflections the Force is the first derivative and a Quaternion Force. Force F= XW = [d/dr, DEL][ -vh/r ,cP] F = [vh/r2 -cDEL.P, cdP/dr -DEL vh/r + cDELxP] F = [vp/r - cp/r cos(P), -cp/r 1P + vp/r 1R + cp/r sin(P) 1RxP] F = cp/r[v/c -cos(P), -1P + v/c 1R + sin(P) 1RXP] cp/r = cp/ct=p/t = mv/t = ma. The vector energy provides the centrifugal force that keeps the mass m from falling into the center. The centrifugal force is teh Divergence of the vector energy, cDEL.P = -cp/r cos(P).
Newton's First Law of Motion describes how an object in circular motion will continue moving in a straight line without any external force acting on it. Newton's Second Law of Motion describes how a force is required to keep an object in circular motion by constantly changing its direction. Finally, Newton's Third Law of Motion states that for every action force (centripetal force) there is an equal and opposite reaction force (centrifugal force) that keeps the object in circular motion.
the difference between force and motion is simple. force is described as the amount of pressure that is applied. motion is a certain movement and it is the result of the force or simply the given potential energy.
1L, 1D, 1L, 2D, 2U, 1R, 2U, 1L, 1R, 2D, 1L, 1U, 2L, 1D, 1R, 1D, 1R, 1U, 2D, 1R, 1D, 3R, 1U, 1R, 6U, 2L, 1U, 3L, 1D, 1L, 2D, 1L, 2D, 3R, 1U, 2R, 1U, 1R, 1U, 1D, 1L, 1D, 2L, 1D, 3L, 2U, 1R, 2U, 2R, 1U, 2R, 1D, 1R, 2D, 1L, 1D, 2L, 1D, 1L, 2D, 1R, 1D, 3R, 1U, 1R, 4U, 2L, 1D, 1R, 1U, 1R, 3D, 2U, 2L, 1D, 1R, 1U, 1R, 1D, 1L, 1D, 2U, 3L, 1D, 3L, 2U, 1R, 1D, 5R, 1D, 1R, 1U, 7L, 1D, 1R, 1D, 1R, 1U, 1L, 1U, 5R, 3L, 1U, 1L, 1D, 4R, 3U, 1L, 1U, 3L, 1D, 1L, 2D, 1L, 1D, 5R, 1U, 1R, 1D, 1L, 1D, 1R, 1L, 1U, 4L, 3U, 1R, 2D, 1L, 1D, 4R, 1D, 1R, 3U
The solution to the Largo Winch latch puzzle is as follows: Key: 1-Ist latch from top R-Right 2-2nd latch from top L-Left 3-3rd latch from top 4-4th latch from top Solution: 1L-2L-1L-3L 1R-2R-1R-3L 1L-2L-1L-4L 1R-2R-1R-3R 1L-2L-1L-3R 1R-2R-1R-4L 1L-2L-1L-3L 1R-2R-1R-3L 1L-2L-3L
-1r
-1
The letters means the direction to move (l:Left,r:Right,u:Up,d:Down) and the digits are the count of moves you have to do (i.e. 3d means 3 moves down) 1l 3d 5l 1d 1l 1u 1l 1u 1r 1d 6r 1u 2r 3d 1l 1d 1u 2r 1d 1l 4u 3l 1d 6l 1d 1l 3d 1l 2d 1r 1u 7r 4u 1l 1u 4l 4u 4r 1d 2r 3d 5l 1d 3l 3d 1l 2d 1r 1u 10r 5u 1r 1u 2l 1r 6d 3l 5u 1r 2u 2d 5l 1d 2l 2u 1r 3u 4r 1d 2r 1u 2r 1d 4l 1d 1l 1u 3r 3d 1l 3d 2r 2l 2d 3r 5u 1r 1u 2l 1r 4d 3l 3u 1r 2u 2d 5l 1d 2l 2u 1r 3u 2r 1d 2r 1u 2l 2r 1d 2r 1u 2r 1d 4l 1u 2l 1d 1r 1u 1r 1d 2r 3d 1l 5d 2r 1u 1d 2l 2u 2r 1d 1r 4u 1r 1u 2l 1r 4d 3l 3u 1r 2u 2d 5l 1d 2l 2u 1r 3u 2r 1d 2r 1u 2l 2r 1d 2r 1u 2r 1d 4l 1u 1l 1d 3r 2d 2r 6d 3r 5u 2l 2r 5d 3l 5u 1r 1u 2l 1r 4d 3l 3u 1r 2u 2d 5l 1d 2l 2u 1r 3u 2r 1d 4r 3d 5l 1d 1l (2u) 2d 2l 3d 1l 2d 1r 1u 2r 2u 1r 2u 1l 1u 4r 4l 1d 3l 2u 1l 1d 1l 1d 5r 1u 1r 1d 3l 3d 1l 2d 1r 4u 3d 7r 4u 1l 1u 5l 1d 2l 1u 2l 1d 4r 1l 4d 2r 1u 1l 1d 1l 3u 3d 10r 6u 2l 2u 4l 1u 2l 3d 1l 2d 2l 2r 4d 7r 4u 1l 1u 3l 1d 1l 1u 4r 1d 1r 4d 7l 4u 1r 2l 1u 2l 1d 3r 4d 10r 6u 2l 2u 2l 1u 1l 1r 1d 2r 1u 2r 1d 5l 3r 3d 6l 5r 5d 3l 2u 1r 1u 1r 1l 1d 1l 2d 3r 4u 2d 3r 4u 2l 1d 5l 3r 2d 1l 1d 2l Gerald
23
0.076
1r 1804 CAT
1R-1808 caterpillar oil filter
1) Move top left box one to the right 2) Move bottom left box one to the right 3) Move middle left box up one 4) Move remaining middle box one to the right 5) Move left side lower box one to the left 6) Move right side lower box two to the left 7) Move top right box one to the left 8) Move moddle right box one down and then one to the left 9) Move remaining boxes on left to final positions
Paksat 1R at 38.0°EFreq 4047 V 3255 3/4
sarcastic