M L T are the units.
M represents Mass, L represents Length and T represents Time.
These are the fundamental units and all other units are derived from these three.
Example: Velocity is MLT-1
The physics equation for the period of a pendulum is T 2(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.
The period of a pendulum can be calculated using the formula T = 2π√(L/g), where T is the period, L is the length of the pendulum (0.500 m in this case), and g is the acceleration due to gravity (approximately 9.81 m/s^2). Plugging in the values, the period of the pendulum with a length of 0.500 m can be calculated.
The dimensional formula of force is ([M] \cdot [L] \cdot [T]^{-2}), where ([M]) represents mass, ([L]) represents length, and ([T]) represents time.
The dimensional formula of electric potential is [M L^2 T^-3 I^-1], where M represents mass, L represents length, T represents time, and I represents electric current.
The dimensional formula of voltage is [M L^2 T^-3 I^-1], where M represents mass, L represents length, T represents time, and I represents electric current.
M. T. Sprackling has written: 'Thermal physics'
Tonic solfa for Silent Night on the recorder: s l s m s l s m r r t d d s l l d t l s l s m l l d t l s l s m r r f r t d m d s m s f r d.
L-E-G-I-T-I-M-A-T-E
The physics equation for the period of a pendulum is T 2(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.
Decode - A M L A E S T T A N G D A
A L M E M H K T
Remove = S I X L E T T E R S = to get = M A T H E M A T I C S =
t-i-m-e t-r-a-v-e-l-l-e-r
trammel
lamented has all but one m
t b o t d i a b w a l o p w d i m t t a l
When calculating dimensions, you look at the measurement units and ignore the numbers associated with them. Dimensions are represented in square brackets. [L] is a single dimension in length, [T] is time and [M] is mass. [L2] represents length in 2 dimensions - or an area. Slightly more complex are density = [M][L-3] or [M]/[L3] Addition of subtraction can only be carried out on identical dimensions and the result is the same "term". Thus [L2] + [L2] = [L2]. The rules for combination may look strange mathematically, but if you describe the equation in words they may be clear. Add an area to an area and you get and area. Multiplication and division are "normal" and, if you are familiar with indices, they are straightforward. Here is an interesting example of where dimensional analysis can take you. Velocity = [L][T-1] Acceleration = (Change in velocity)/Time = ([L][T-1] - [L][T-1]) / [T] but [X] - [X] = [X] (see rules for addition and subtraction above) = ([L][T-1]) /[T] = [L][T-2] Force = Mass*Acceleration = [M]*[L][T-2] = [M][L][T-2] Energy or mechanical Work = Force*Distance Moved = [M][L][T-2]*[L] = [M][L2][T-2] = [M]*([L][T-1])2 But [L][T-1] is the dimensional representation of velocity So, we have Energy = [M]*velocity2 Or e =mc2 which you may have come across before!