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OMEGA2 is a decentralized finance (DeFi) platform that aims to provide various financial services, such as lending, borrowing, and yield farming, to its users. It is built on the Binance Smart Chain network, offering users the opportunity to participate in the growing DeFi ecosystem.
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How do find centripetal force?
By newton's second law: force = mass x acceleration. Acceleration can be found by the formula a = v2/r, or alternately, a = omega2 x r (where v is the speed, r is the radius, and omega is the angular velocity in radians/second).
What does Centrifugal forces increases with?
This is centripetal force Fc = mv2/r, so an increase of mass or velocity and a decrease of radius will increase the centripetal force (or send the object flying away quite fast).. Centrifugal force is only a feeling of being pushed to the outside, based on human perception
When the mass and the radius are held constant what happens to the centripetal force if the frequency of the rotation is increased?
One formula to calculate centripetal acceleration is: a = omega2r, where omega is the angular velocity. Combining this with Newton's Second Law: F=ma you get: F = m omega2 r For completeness sake, omega (in radians per second) = 2 pi f (2 x pi x the frequency, in revolutions / second). Thus, omega and the frequency are proportional. As you can see, the force is proportional to the square of the angular velocity. For example, doubling the frequency would cause double the angular velocity, which would require an increase of the force by a factor of 4.
How do you calculate the centripetal acceleration of an object?
ac = v2/r, where the variables are: * 'a' is the centripetal acceleration in metres per second per second; * 'v' is the tangential velocity in metres per second; and * 'r' is the radius of motion in metres.
When is alpha and omega 2 coming out?
It is coming out in 2013.I hope you like alpha and omega2 when it comes out.
What is the centripetal force of a half kilogram ball that moves in a circle 0.4 m in radius at a 4 meter per second speed?
You solve this in two steps. First, you calculate the centripetal acceleration, using the formula a = v2/r. (Another commonly used formula is omega2 times r, but the first formula is easier to use in this case.) Second, you use newton's second law: force = mass x acceleration.
What is the centripetal acceleration of a stone with a radius of 0.75 meters and a height of 1.5 meters and travels a horizontal distance of 4 meters?
I don't think you have enough information. Here are two formulae to calculate centripetal acceleration: a = v2 / r a = omega2 x r (omega is the angular speed, in radians per second) Basically, apart from the radius you also need to know (or have enough information to calculate) the speed (or equivalently, the angular speed).
Is a centrifugal force the same as the centripetal force?
Answer: no..while centrifugal force is about something going away from the center of rotation, the centripetal force means getting pulled towards the center of circle. Answer: Also, the centripetal force is a real force, while the centripetal force is a ficticious force - or a force that only appears in a rotating frame of reference. For purposes of calculation, the magnitude of both forces is the same, and same formulas can be applied: F = ma, and either a = v2/r, or a = omega2 x r.
What is the magnitude of the acceleration of a speck of clay on the edge of a potter's wheel turning at 48 RPM revolutions per minute if the wheel's diameter is 42 cm?
Two formulas are commonly used for centripetal acceleration: 1) a = v2/r (v = speed, r = radius) 2) a = omega2 x r (omega = angular speed, r = radius) Formula 2 seems simpler to use in this case. Note that the angular speed must be in radians/second, so you must first convert rpm to radians per secnd.
How do find centripetal force?
By newton's second law: force = mass x acceleration. Acceleration can be found by the formula a = v2/r, or alternately, a = omega2 x r (where v is the speed, r is the radius, and omega is the angular velocity in radians/second).
What does Centrifugal forces increases with?
This is centripetal force Fc = mv2/r, so an increase of mass or velocity and a decrease of radius will increase the centripetal force (or send the object flying away quite fast).. Centrifugal force is only a feeling of being pushed to the outside, based on human perception
When the mass and the radius are held constant what happens to the centripetal force if the frequency of the rotation is increased?
One formula to calculate centripetal acceleration is: a = omega2r, where omega is the angular velocity. Combining this with Newton's Second Law: F=ma you get: F = m omega2 r For completeness sake, omega (in radians per second) = 2 pi f (2 x pi x the frequency, in revolutions / second). Thus, omega and the frequency are proportional. As you can see, the force is proportional to the square of the angular velocity. For example, doubling the frequency would cause double the angular velocity, which would require an increase of the force by a factor of 4.
What should the angular speed of the earth for the centrifugal force to equal the force of gravity?
Use the formula for centripetal acceleration; actually, one of the following two: a = v2/r, or: a = omega2 x r The second one is probably less effort for this particular problem. Replace a = 9.8 meters per second square (since that is Earth's gravity), and solve for omega. a = acceleration (in SI units, meters per second square). v = speed (in SI units, meters/second) r = radius (Earth's radius, should be in meters) omega = angular speed (in radians per second).
What is order instrument?
A second order linear instrument has an output which is given by a non-homogeneous second order linear differential equationd2y(t)/dt2 + 2.rho.omega.dy(t)/dt + omega2.y(t) = K.omega2.x(t),where rho is a constant, called the damping factorof the instrument, and omega is a constant called the natural frequency of the instrument.Under a static input a second order linear instrument tends to oscillate about its position of equilibrium. The natural frequency of the instrument is the frequency of these oscillations.Friction in the instrument opposes these oscillations with a strength proportional to the rate of change of the output. The damping factor is a measure of this opposition to the oscillations.An example of a second order linear instrument is a galvanometer which measures an electrical current by the torque on a coil carrying the current in a magnetic field. The rotation of the coil is opposed by a spring. The strength of the spring and the moment of inertia of the coil determine the natural frequency of the instrument. The damping of the oscillations is by mechanical friction and electrical eddy currents.Another example of a second order linear instrument is a U-tube manometer for measuring pressure differences. The liquid in the U-tube tends to oscillate from side to side in the tube with a frequency determined by the weight of the liquid. The damping factor is determined by viscosity in the liquid and friction between the liquid and the sides of the tube.
What is second order instrument?
secondary instruments,as opposed to absolute instruments ,are direct reading type instruments.the value of an electrical quantity can be read directly from the deflection shown on the instruments.deflections on an un-calibrated secondary instrument are not a true measure of the electrical quantites.
How do you calculate the centripetal acceleration of an object?
ac = v2/r, where the variables are: * 'a' is the centripetal acceleration in metres per second per second; * 'v' is the tangential velocity in metres per second; and * 'r' is the radius of motion in metres.
