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One byproduct of photoelectric absorption is the ejection of an electron from an atom. This process occurs when a photon's energy is entirely absorbed by an atom, causing an electron to be released from its orbit around the nucleus. This electron can go on to contribute to electrical conductivity or ionization processes.

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Is photoelectric absorption high kvp?

No, photoelectric absorption decreases with increasing photon energy (kVp). This is because higher-energy photons are more likely to be transmitted through the material or undergo Compton scattering rather than being absorbed through the photoelectric effect.


What is the difference between Compton scattering and the photoelectric effect in terms of their interactions with photons?

Compton scattering involves the collision of a photon with an electron, resulting in the photon losing energy and changing direction. The photoelectric effect, on the other hand, involves the absorption of a photon by an electron, causing the electron to be ejected from the material. In summary, Compton scattering involves the photon changing direction and losing energy, while the photoelectric effect involves the absorption of the photon by an electron.


What is the difference between field emission and photoelectric emission?

* emisssion of electron from the surface of the metal when light of suitable frequency falls-photoelectric emission. * emision of electron from the metal by quantum tunnling of electron.


Why photoelectric measurement are so sensitive to the nature of photoelectric surface?

Photoelectric measurements are sensitive to the nature of the photoelectric surface because the surface properties, like work function and reflectivity, directly affect the efficiency of electron emission when photons are absorbed. The surface characteristics influence the energy required for electron liberation, impacting the overall photoelectric effect.


Does thickness has effect on absorption of gamma ray by lead?

Yes, the thickness of lead does have an effect on the absorption of gamma rays. A thicker layer of lead will be more effective at absorbing gamma rays compared to a thinner layer. This is because gamma rays interact with matter through processes like photoelectric absorption and Compton scattering, which are more likely to occur with a greater thickness of lead material.

Related Questions

Is photoelectric absorption high kvp?

No, photoelectric absorption decreases with increasing photon energy (kVp). This is because higher-energy photons are more likely to be transmitted through the material or undergo Compton scattering rather than being absorbed through the photoelectric effect.


What is the difference between Compton scattering and the photoelectric effect in terms of their interactions with photons?

Compton scattering involves the collision of a photon with an electron, resulting in the photon losing energy and changing direction. The photoelectric effect, on the other hand, involves the absorption of a photon by an electron, causing the electron to be ejected from the material. In summary, Compton scattering involves the photon changing direction and losing energy, while the photoelectric effect involves the absorption of the photon by an electron.


What is photoionization?

The removal of one or more electrons from an atom or molecule by absorption of a photon of visible or ultraviolet light. (Also known as atomic photoelectric effect.)


Can photoelectric effect be observed using infrared rays?

No, the photoelectric effect is the emission of electrons from a material due to the absorption of photons. Infrared rays have lower energy photons than visible light, so they are not typically energetic enough to cause the photoelectric effect. Only photons with enough energy, such as ultraviolet or higher energy photons, can induce the photoelectric effect.


Why photoelectric measurements are so sensitive to the nature of photoelectric surface?

why are photoelectric measurements are so sensitive to the nature of the photoelectric surface


What is the difference between field emission and photoelectric emission?

* emisssion of electron from the surface of the metal when light of suitable frequency falls-photoelectric emission. * emision of electron from the metal by quantum tunnling of electron.


Why photoelectric measurement are so sensitive to the nature of photoelectric surface?

Photoelectric measurements are sensitive to the nature of the photoelectric surface because the surface properties, like work function and reflectivity, directly affect the efficiency of electron emission when photons are absorbed. The surface characteristics influence the energy required for electron liberation, impacting the overall photoelectric effect.


Does thickness has effect on absorption of gamma ray by lead?

Yes, the thickness of lead does have an effect on the absorption of gamma rays. A thicker layer of lead will be more effective at absorbing gamma rays compared to a thinner layer. This is because gamma rays interact with matter through processes like photoelectric absorption and Compton scattering, which are more likely to occur with a greater thickness of lead material.


What is the difference between ionization and photoelectric processes in terms of their interaction with matter?

Ionization is the process of removing an electron from an atom or molecule, creating an ion. This process can occur through collisions with high-energy particles. On the other hand, the photoelectric effect involves the ejection of an electron from a material when it absorbs a photon of sufficient energy. In terms of their interaction with matter, ionization can occur through various mechanisms, while the photoelectric effect specifically involves the absorption of photons to release electrons.


Why are photoelectric measurement so sensitive to the nature of the photoelectric surface?

why are photoelectric measurements are so sensitive to the nature of the photoelectric surface


What is meant by photoelectric colorimeter?

Photoelectric colorimeter is a medical term. Essentially, it is referring to a colorimeter using a photoelectric cell and appropriate filters instead of the eye.


Match the experimental conditions applied to the photoelectric effect observed.?

conditions of photoelectric effect