That means the constant has a value that is different to zero.
That means the constant has a value that is different to zero.
That means the constant has a value that is different to zero.
That means the constant has a value that is different to zero.
That means the constant has a value that is different to zero.
That means the constant has a value that is different to zero.
That means the constant has a value that is different to zero.
the electrical
Acceleration is the rate of change in velocity. When velocity is constant, it is NOT CHANGING so acceleration is negligible or ZERO or non-existent.
no
Whenever velocity is constant, the acceleration is zero. This also works when the velocity is zero, the acceleration is zero. That pretty much means the object isn't moving. But, yes/ If velocity is constant, accleration is zero.
No. If the sum of all the forces on the object is not zero, then the object's acceleration is not zero, meaning that either its speed or direction of motion, or both, are changing.
It is non-zero.It is non-zero.It is non-zero.It is non-zero.
That degree is zero.
There is almost never an "IF". All non-zero vectors have a constant, specified direction. Only a zero-vector has a direction which is unspecified.
the electrical
If x^2 is second degree, and x (which is x^1) is first degree, then a constant would be zeroth degree, I think since x^0 = 1 for any non-zero x.
If an object is sustaining a constant velocity it has 0 acceleration, because acceleration is either increasing or decreasing speed.
The derivate of zero - as well as the derivative of ANY constant (non-variable) number, is zero. (A graph of y = 0 for example will be a horizontal line - the slope is zero.)
Acceleration is the rate of change in velocity. When velocity is constant, it is NOT CHANGING so acceleration is negligible or ZERO or non-existent.
A straight line with a constant slope
Nein. If it's moving, by definition it has non-zero velocity.
The only non-exponential function that has this property would be a function that has the constant value of zero.
Yes, a falling apple meets that condition.