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No, they don't have de-broglie wavelength since this concept is valid for substances having some mass. This concept is mainly used to calculate the wavelength of electrons.

The photons are just energy packets and they are not matter and don't have weight.

Therefore, they don't have de-broglie wavelength

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p=h/lambda

so lambda=h/p

but E=hf=hc/lambda

so lambda=hc/E

hence lambda=hc/E

relates wavelength (lambda) to the energy of a photon

1.8 [Å] = 1.8*10-10 [m]

Q: What is de broglie wavelength of one photon?

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Yes

The de Broglie wavelength of a proton becomes shorter.

The De Broglie Wavelength is being measured in the electromagnetic fields. The De Broglie Wavelength theory is related to Bohr's Quantum Theory and is about the energy of atom particles.

de Broglie wavelength depends only on the mass and speed of the particle and not on the temperature

Because such a wavelength is way too small to be significant. The de Broglie wavelength is inversely proportional to an object's momentum (mass x speed).

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Yes

The de Broglie wavelength of a proton becomes shorter.

The De Broglie Wavelength is being measured in the electromagnetic fields. The De Broglie Wavelength theory is related to Bohr's Quantum Theory and is about the energy of atom particles.

de Broglie wavelength depends only on the mass and speed of the particle and not on the temperature

The de Broglie Wavelength of a mosquito can be calculated using a specific formula. For this example, the wavelength is 2.8 to the 28th power meters.

1924

Because such a wavelength is way too small to be significant. The de Broglie wavelength is inversely proportional to an object's momentum (mass x speed).

It can. See link for de Broglie wavelength.

Wavelength equals Planck's Constant divided by momentum.

use de Broglie's wavelength: lambda = h/mv

wavelength

it's 9.962x10-32 cm