This is the vertical motion model, used when solving for height that an object is dropped from, what height an object is at after so many seconds, what rate the object is falling at, and how many seconds have passed after dropping an object when it is at x height etc. etc. Most often used in Algebra 1 and 2.
In physics, the keyword "s vt 2" represents the equation for calculating displacement (s) using velocity (v) and time (t). This equation is significant because it helps determine how far an object has moved in a given amount of time. It relates to the concept of velocity and time by showing that the displacement of an object is directly proportional to its velocity and the time it has been moving.
The acceleration of the vehicle can be calculated using the formula: acceleration = change in velocity / time. First convert the velocity from km/h to m/s (500 km/h = 138.89 m/s). The change in velocity is 138.89 m/s (final velocity) - 0 m/s (initial velocity) = 138.89 m/s. So, the acceleration is 138.89 m/s / 20 s = 6.9445 m/s^2.
To convert m/s into km/hr, you multiply by 18/5. So 36 m/s is 129.6 km/hr
120 km per hour = 33.33 meters per second.
Answer : potential energy (PE) = m *g *h m= mass of object (kg) g= gravity = 10 m/s2 h= height (m) PE = m *g *h 9800 = 200 * 10 *h 9800= 2000 h h= 4.9 m
S=vt-16t2 solve for v is what I will assume you mean. first pull out the t S=t(v-16t) then devide by t S/t=v-16t Then add 16t to both sides S/t + 16t = v This can also be written as (S+16t2)/t = v
16t2 + vt - S = 0 This is in the general form of the quadratic equation, and the general quadratic solution can be applied directly. t = [ (-v) plus or minus the square root of (v2 + 64S) ] all divided by 32.
By the Way, guys, this is based on the equation H= -16t2+vt+s
-16t2 + 64t + 1224 = 0 Multiply both sides by -1 16t2 - 64t - 1224 = 0 Divide both side by 8 2t2 - 8t - 153 = 0 Cannot be factored so use the formula (-b (+ or -)(root of b2 - 4ac)) / 2a
formula: h=-16t^2+vt+s H= final height T= time V= velocity S= starting height
v = 45 mph t = 2 minutes = 1/30 h S = ? S = vt S = 45 miles/h x (1/30) h S = 1,5 miles
F(t) = h - 16t2
9 minutes
H= -1/2gt2+vt+s Where H is the ending height g is the rate of gravity (32 ft/sec2 or 9.8 m/sec2) t is the time v is the initial velocity and s is the starting height.
Frank Clyde Wright has written: 'An historical pamphlet' -- subject(s): Barnet, Vt. Congregational Church, McIndoe Falls, Vt. Congregational Church, Vt Barnet, Vt McIndoe Falls
shrug means 1 VT to s. one's
0,16 1,49