The net force is 150 N. When forces are added in the same direction, the net force is the sum of the individual forces.
The acceleration is 0. That also means that the net force is 0N since the gravity Force is 100N down and the bag of nails is 100N, the air resistance must be 100N up to balance it out and create the net force of 0N
The net force is the sum of the individual forces, so the net force would be 13.0 N in this case.
The net force on the barrel is the difference between the force of the barrel and the force of the pavement: 6000 N - 2000 N = 4000 N. Therefore, the net force on the barrel as it hits the pavement is 4000 N.
The net force on the book is calculated by subtracting the force of friction from the force applied by the student. In this case, the net force is 2 N (6 N - 4 N).
The net force on the box is the difference between the applied force and the force of friction. In this case, the net force on the box is 13 N (20 N - 7 N) in the direction of the applied force.
The acceleration is 0. That also means that the net force is 0N since the gravity Force is 100N down and the bag of nails is 100N, the air resistance must be 100N up to balance it out and create the net force of 0N
The net force would be zero, which means the falling object would no longer be accelerating, and would be falling at terminal velocity, which is a constant velocity. Weight is a downward (negative) force and air resistance is an upward (positive) force. Fnet = weight + air resistance = -12N + 12N = 0N
The net force is the sum of the individual forces, so the net force would be 13.0 N in this case.
Assuming the force of friction and the initial force oppose each other the net force is 300 N - 200 N = 100 N in the direction of the initial force.
The net force on the barrel is the difference between the force of the barrel and the force of the pavement: 6000 N - 2000 N = 4000 N. Therefore, the net force on the barrel as it hits the pavement is 4000 N.
The net force in the east-west direction is 0 N as the forces cancel out. In the north direction, the net force is 5 N upwards.
The net force on the book is calculated by subtracting the force of friction from the force applied by the student. In this case, the net force is 2 N (6 N - 4 N).
You will have to learn a new terminology here: net force. Net force is the sum of all forces acting on an object. For example, in a tag of war, when one team is pulling the tag with a force of 100 N and the other with 80 N, the net force would be 20 N at the direction of the first team (100 N - 80 N = 20 N).
The net force on the box is the difference between the applied force and the force of friction. In this case, the net force on the box is 13 N (20 N - 7 N) in the direction of the applied force.
This question cannot be answered without knowing the acceleration of the box.
The net force on the object is 5 newtons toward the north.
The net force on the object is 5 newtons toward the north.