Horizontal force in one component of the magnetic force on earth. Horizontal is a direction, and force is any external efforts that causes an object to change.
No, the horizontal component of a force is directly related to the magnitude of the force. Increasing the horizontal component of the force would require increasing the magnitude of the force itself.
The horizontal friction coefficient can be calculated using the formula: μ = F_h / N, where μ is the friction coefficient, F_h is the horizontal friction force, and N is the normal force acting on the object. The horizontal friction force can be calculated as F_h = μ* N, where N is the normal force and μ is the friction coefficient.
The horizontal force can be calculated using the formula Fhorizontal = Fcos(θ), where F is the given force (20N) and θ is the angle of inclination (30 degrees). Plugging in the values, we get Fhorizontal = 20N x cos(30) ≈ 17.3N.
No, a horizontal force that is less than the weight of an object will not be able to move the object. In order to move the object, the horizontal force must be greater than or equal to the weight of the object.
In a coordinated turn, centrifugal force acts as the horizontal force that helps to balance the horizontal lift component generated by the aircraft. The centrifugal force pulls the aircraft outward in a turn, while the horizontal lift component works to turn the aircraft. Together, they work to maintain the aircraft's trajectory in a coordinated turn.
No, the horizontal component of a force is directly related to the magnitude of the force. Increasing the horizontal component of the force would require increasing the magnitude of the force itself.
It is acceleration in the horizontal direction. This would happen as a result of a net horizontal force acting on a body.
The horizontal friction coefficient can be calculated using the formula: μ = F_h / N, where μ is the friction coefficient, F_h is the horizontal friction force, and N is the normal force acting on the object. The horizontal friction force can be calculated as F_h = μ* N, where N is the normal force and μ is the friction coefficient.
There is not enough information to answer this question.
The horizontal force can be calculated using the formula Fhorizontal = Fcos(θ), where F is the given force (20N) and θ is the angle of inclination (30 degrees). Plugging in the values, we get Fhorizontal = 20N x cos(30) ≈ 17.3N.
That is difficult to answer in that a horizontal force may be perpendicular to the body. So, the question does not differentiate between "can a vertical force cancel a horizontal force?" and "can a horizontal force cancel a horizontal force?" The best answer is, yes: two opposite and equal horizontal forces, both perpendicular to a body, will cancel each other.
No, a horizontal force that is less than the weight of an object will not be able to move the object. In order to move the object, the horizontal force must be greater than or equal to the weight of the object.
In a coordinated turn, centrifugal force acts as the horizontal force that helps to balance the horizontal lift component generated by the aircraft. The centrifugal force pulls the aircraft outward in a turn, while the horizontal lift component works to turn the aircraft. Together, they work to maintain the aircraft's trajectory in a coordinated turn.
Yes, but any bit of force in any horizontal direction is always exactly cancelled by an equal-size bit of force in the opposite horizontal direction, so there's never a NET horizontal buoyant force. It's only apparent in the upward vertical direction.
The amount of horizontal force required to start in motion an object sitting on a horizontal surface must be greater than the force of static friction acting on the object. This is because the force of static friction opposes the applied force until the object starts moving.
The force that causes horizontal motion is typically friction generated between the object and the surface it is moving on. Additionally, propulsion forces such as from engines or a person pushing can also contribute to horizontal motion.
The force applied by the person can be broken down into horizontal and vertical components. The vertical component will help support the weight of the box while the horizontal component will maintain the box against the wall. The frictional force between the box and the wall will counteract the horizontal force.