The units used to measure length, width, and height should be the same to calculate volume in cubic units. For example, if length, width, and height are measured in meters, then the volume will be in cubic meters. It is crucial to maintain consistency in units to ensure accurate volume calculations.
A graduated cylinder or beaker is typically used to measure the volume of a regular shaped object by filling it with water and measuring the change in volume. The difference in water level before and after submerging the object gives the volume.
LxWxH=Answer _ cm3
Assuming that the shape of the stadium is a rectangular prism, and using the equation for the area of a rectangular prism (LxWxH=V) you can say that 600x400x100=V 240000x100=V 24000000=V The number of cubic feet that it would take to fill the stadium is 24000000 cubic feet.
When the total weight of the ship is less than the weight of the volume of water (salt or fresh) that the ship displaces, it will float. You can make a ship out of steel or concrete, as long as it weighs less than the volume of water it displaces. How sea-worthy the ship is depends on what type of waves or what the possiblity is of the ship taking on water, unless the exterior is sealed. To calculate this, you will need the exterior dimensions of the hull and weight of the ship. I would use the metric system, because the units are easier to convert for this example. Kilograms (1000-grams) for weight and Liters (1000-cubic centimeters) for volumes. Using a volumetric formula (i.e. length x width x height) to obtain the volume you wish to be below the water line. Take the weight of the ship and divide it by the volume you obtained for the ship at or under the water-line. If this number is less than the specific-gravity of fresh water (lighter than salt water) it will float, provided the center of gravity is on the bottom of the ship. (otherwise it may turn up-side down). The specific gravity of water is ~1.0 kilogram per Liter. For example if the volume (LxWxH) displaced (below the water line) by the ship is 100 liters and the weight of the whole ship is 60 kilograms, 60/100 = 0.6 which is less than the water specific gravity 1.0, then it should float. Bear in mind that the ~70% of the weight of the ship should be below the water line or the ship will not have stability (it may turn over). This should also take into account added weight to the ship such as cargo or (God forbid) water.
The volume.
LxWxH
lxwxh
Depends on the shape of the object and what subject. Math volume is LxWxH.
LxWxH=Answer _ cm3
LxWxH=Answer _ cm3
it is lxwxh (width x hight)
LXWXH= volume find the mass and divide it with the volume mass divided by volume equals density
LxWxH (lengeth times width times height)
LxWxH it is 28ft2
LXWXH
V=LxWxH (Volume equals length times width times hight) FaCK YOU DID DO THAT JEW