Any curved line will indicate a change in acceleration. Straight lines with slope indicate a steady velocity and straight lines with zero slope indicate a lack of motion.
If the X axis (left to right) is for time and the Y axis (up and down) is for speed, it would curve up.
On a velocity-time graph, increasing speed (acceleration) is represented by a line with a positive slope.
A bobsled's distance-time graph indicates that it traveled 100 m in 25 s. What is the bobsled's speed
Accelerated motion is represented by a _____ line on a nonlinear distance-time graph.
If the graph is a horizontal line, then the velocity is constant, and acceleration is zero.
Ahorizontal line on a velocity vs time graph does not indicate any acceleration because there is no slope. Speed remains constant.
The graph of acceleration vs time for an object moving at constant velocity is a straight horizontal line that coincides with the x-axis, i.e. it's the line [ y = 0 ].
When the acceleration of a particle is constant, the velocity will be increasing at a constant rate. This means that the velocity versus time graph will appear with a straight line "slanting up to the right" in the first quadrant. With time on the x-axis and velocity of the y-axis, as time increases, velocity will increase. That means the line will have a positive slope. The higher the (constant) acceleration, the greater the slope of the line. If we take just one example and mark equal units off on our axes, and then assign seconds along the x-axis and meters per second along the y-axis, we can plot a graph for an acceleration of, say, one meter per second per second. Start at (0,0) and at the end of one second, the velocity will be one m/sec. That point will be (1,1). After another second, the velocity will be 2 m/sec owing to that 1m/sec2 rate of acceleration, and that point will be (2,2). The slope of the line is 1, which is the rate of acceleration.
The slope of a line on a velocity-time graph is acceleration.
If the graph is a straight line, then the slope of the line is the average acceleration of the ball.
Ahorizontal line on a velocity vs time graph does not indicate any acceleration because there is no slope. Speed remains constant.
false
false
a horizontal line
a horizontal line
This depends on what the graph represents. If it is a graph of velocity on the vertical and time on the horizontal, then if acceleration is at a constant rate, the graph will be a straight line with positive slope (pointing 'up'). If acceleration stops, then the graph will be a horizontal line (zero acceleration or deceleration). If it is deceleration (negative acceleration), then the graph will have negative slope (pointing down).
Constant velocity implies zero acceleration, so you would have a horizontal line, identical to the x-axis.
the gradient of the graph
The graph of acceleration vs time for an object moving at constant velocity is a straight horizontal line that coincides with the x-axis, i.e. it's the line [ y = 0 ].
An object moving with uniform acceleration has a uniform change in velocity over time, and its velocity-time graph will be a straight line with either a positive or negative slope. An object moving with no acceleration has constant velocity, and its velocity-time graph will be a straight, horizontal line with zero slope. Refer to the related link for illustrations.
a horizontal line :)
When the acceleration of a particle is constant, the velocity will be increasing at a constant rate. This means that the velocity versus time graph will appear with a straight line "slanting up to the right" in the first quadrant. With time on the x-axis and velocity of the y-axis, as time increases, velocity will increase. That means the line will have a positive slope. The higher the (constant) acceleration, the greater the slope of the line. If we take just one example and mark equal units off on our axes, and then assign seconds along the x-axis and meters per second along the y-axis, we can plot a graph for an acceleration of, say, one meter per second per second. Start at (0,0) and at the end of one second, the velocity will be one m/sec. That point will be (1,1). After another second, the velocity will be 2 m/sec owing to that 1m/sec2 rate of acceleration, and that point will be (2,2). The slope of the line is 1, which is the rate of acceleration.