(1/4pi[epsilon]_0)*Q^2/2R
This can be derived from the fact that a spherical shell seemingly has a potential of a point charge (that is, k*Q/R) and W =½ int Vdq, where dq can be replaced with a [sigma]dA=[sigma] 4 pi r dr and sigma= Q/A = Q/4piR^2 => int½ Vdq = int ½k*Q/r*Q/(4piR^2)*4pir dr from 0 to R = k*½*Q^2/R^2 int dr from 0 to R = ½kQ^2/r=k*Q^2/2r.
in spherical capacitor two concentric sphere are taken of different radii. one is charged uniformly and placed inside other of greater radii. due to electric induction negative charge come at inner part of second sphere and positive charge come at outer sphere. to vanish this charge we earthed it. only negative charge remains on inner surface which decrease potential of first charged sphere and increase capacity.
The voltage inside a uniformly charged sphere is directly related to the distribution of charge within the sphere. As the charge distribution becomes more uniform, the voltage inside the sphere becomes more evenly distributed. This means that the voltage is higher towards the center of the sphere where the charge is concentrated, and decreases towards the surface where the charge is spread out.
The electric field of a uniformly charged sphere is the same as that of a point charge located at the center of the sphere. This means that the electric field is radially outward from the center of the sphere and its magnitude decreases as you move away from the center.
The formula for calculating the electrostatic energy of a spherical shell is U (Q2)/(8R), where U is the electrostatic energy, Q is the charge on the shell, is the permittivity of free space, and R is the radius of the shell.
The electric field equations for different geometries are: For a point charge: E kq/r2, where E is the electric field, k is the Coulomb's constant, q is the charge, and r is the distance from the charge. For a uniformly charged infinite line: E 2k/r, where E is the electric field, k is the Coulomb's constant, is the charge density, and r is the distance from the line. For a uniformly charged infinite plane: E /2, where E is the electric field, is the surface charge density, and is the permittivity of free space.
in spherical capacitor two concentric sphere are taken of different radii. one is charged uniformly and placed inside other of greater radii. due to electric induction negative charge come at inner part of second sphere and positive charge come at outer sphere. to vanish this charge we earthed it. only negative charge remains on inner surface which decrease potential of first charged sphere and increase capacity.
From Gauss's Law, Electric Field inside is 0, and it's electric flux is equal to Qenclosed/Eo, where Eo is the electric vacuum permittivity constant. Also, outside of the sphere, it could be treated as a point charge, where the point lies at the center of the shell and has a charge equal to the total charge of the shell.
The net electrostatic force acting on a charged particle located inside a shell of uniform charge is zero. This is because the electric field inside a uniformly charged shell is zero, meaning there are no forces acting on the charged particle from the shell itself.
Outside a charged spherical shell, the electric field behaves as if all the charge is concentrated at the center of the shell. This is known as Gauss's Law for a spherical surface, which states that the electric field at a distance r from the center of a charged spherical shell is equivalent to that of a point charge with the same total charge as the shell at the center. Therefore, the electric field outside a charged spherical shell decreases with the square of the distance from the center of the shell.
The voltage inside a uniformly charged sphere is directly related to the distribution of charge within the sphere. As the charge distribution becomes more uniform, the voltage inside the sphere becomes more evenly distributed. This means that the voltage is higher towards the center of the sphere where the charge is concentrated, and decreases towards the surface where the charge is spread out.
The electric field of a uniformly charged sphere is the same as that of a point charge located at the center of the sphere. This means that the electric field is radially outward from the center of the sphere and its magnitude decreases as you move away from the center.
The formula for calculating the electrostatic energy of a spherical shell is U (Q2)/(8R), where U is the electrostatic energy, Q is the charge on the shell, is the permittivity of free space, and R is the radius of the shell.
The electric field equations for different geometries are: For a point charge: E kq/r2, where E is the electric field, k is the Coulomb's constant, q is the charge, and r is the distance from the charge. For a uniformly charged infinite line: E 2k/r, where E is the electric field, k is the Coulomb's constant, is the charge density, and r is the distance from the line. For a uniformly charged infinite plane: E /2, where E is the electric field, is the surface charge density, and is the permittivity of free space.
A charged metallic plate is a thin rectangular (or square) sheet that carries a surface charge. Because metal is a conductor, you can assume that the surface charge is spread uniformly over the area of the plate.
The potential electric energy of a charged object is determined by its charge and its position in an electric field. This energy is calculated using the formula U = qV, where U is the potential energy, q is the charge of the object, and V is the electric potential at the object's position.
When a positive charge moves due to a nearby negatively charged object, potential energy is converted into kinetic energy as the positive charge moves closer to the negative object. The potential energy decreases as the positive charge moves towards the negative charge due to the attractive forces between them. This energy change is responsible for the movement of the positive charge.
The vibration of electrically charged particles produces a type of energy known as electromagnetic radiation.