The kinetic energy of a 6 kg mass moving at 4 m/s can be calculated using the formula KE = 0.5 * m * v^2. Plugging in the values, KE = 0.5 * 6 kg * (4 m/s)^2 = 48 Joules.
KE= 1/2mv2 KE=1/2(4)82 KE=2(8)2 KE=162 KE= 256 J So the total is 256 J of Kinetic and Potential Energy
The kinetic energy of the rock can be calculated using the formula KE = 0.5 * mass * velocity^2. Substituting the values, KE = 0.5 * 4 kg * (10 m/s)^2 = 200 J. Thus, the kinetic energy of the rock is 200 Joules.
Kilogram (kg) is the SI unit of mass, so the mass is 4 kg in this case.
1.2 x 10^4 J That is in Significant Figures
(4 kg)*(2 m/s) = 8 kg•m/s
KE= 1/2mv2 KE=1/2(4)82 KE=2(8)2 KE=162 KE= 256 J So the total is 256 J of Kinetic and Potential Energy
The kinetic energy of the rock can be calculated using the formula KE = 0.5 * mass * velocity^2. Substituting the values, KE = 0.5 * 4 kg * (10 m/s)^2 = 200 J. Thus, the kinetic energy of the rock is 200 Joules.
.4875 kilograms but make sure your units are right on your question because that seems very small
Using p=mv. p: momentum (kg ms^-1) m: mass (kg) v: velocity (ms^1) p = (25)(4) = 100 kg ms^-1
Just multiply mass x velocity.
Velocity of 4 meters per second??? I will assume so. ( need kilograms, so... 5 grams = 0.005 kilograms ) KE = 1/2mV2 KE = 1/2(0.005 kg)(4 m/s)2 = 0.04 Joules =============
4 watts 39.2 watts
Kilogram (kg) is the SI unit of mass, so the mass is 4 kg in this case.
1.2 x 10^4 J That is in Significant Figures
4 kg is the mass of the water. Thus, 4 kg of water has a mass of 4 kg.
(4 kg)*(2 m/s) = 8 kg•m/s
m = massV = velocityKE = 1/2 m V216 = 1/2 (0.5) V2V = sqrt( 16/0.25 ) = 8 m/secMomentum = m V = (0.5) x (8) = 4 kg-mtr/sec