the escalator will never have an inclination of 45deg the standard of angle i 30and 35 deg only
The initial velocity is sqrt(5) times the vertical component, and its angle relative to the horizontal direction, is 0.46 radians (26.6 degrees).
At the top of the path, the projectile stops rising and starts falling. The vertical component of velocity at that point is zero.
the vertical component of the balls initial velocity is Ay= 48 sin 45 34m/s
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Yes. For example, a ball thrown vertically in the air has a positive velocity (upwards) but a negative acceleration due to gravity (downwards at ~9.81 m/s^2), until it begins to move downwards.
The initial velocity is sqrt(5) times the vertical component, and its angle relative to the horizontal direction, is 0.46 radians (26.6 degrees).
At the top of the path, the projectile stops rising and starts falling. The vertical component of velocity at that point is zero.
Multiply the speed by the cosine of the angle (25 degrees in this case). For the vertical velocity, multiply by the sine of 25 degrees.Multiply the speed by the cosine of the angle (25 degrees in this case). For the vertical velocity, multiply by the sine of 25 degrees.Multiply the speed by the cosine of the angle (25 degrees in this case). For the vertical velocity, multiply by the sine of 25 degrees.Multiply the speed by the cosine of the angle (25 degrees in this case). For the vertical velocity, multiply by the sine of 25 degrees.
the vertical component of the balls initial velocity is Ay= 48 sin 45 34m/s
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Smaller angles will result in a larger horizontal velocity and smaller vertical velocity. The times of flight will also be shorter since it's closer to the ground. Larger angles have a larger vertical velocity and smaller horizontal velocity. Time of flight will be much longer since it is higher above the ground. As for distance, 45 degrees will result in the greatest distance and for every distance before the furthest one there is an angle above 45 degrees and an angle below 45 degrees that will result in that distance.
Yes. For example, a ball thrown vertically in the air has a positive velocity (upwards) but a negative acceleration due to gravity (downwards at ~9.81 m/s^2), until it begins to move downwards.
Can't say. It depends on the release velocity (muzzle velocity).The maximum horizontal distance always results from an angle of 45 degrees, regardless of the release velocity.
Horizontal component = 14 cos(38) = 11.032 lbs (rounded)Vertical component = 14 sin(38) = 8.619 lbs (rounded)
You have a right triangle and can use trig. Degree mode. tan(theta) = adjacent/opposite( y component ) tan( 60 degrees) = (5 m/s)/(y comp.) y component = 5 m/s)/(tan 60 degrees) = 2.887 m/s ( you can call it 3 m/s ) -----------------------------------------------
If you ignore the effect of the air grabbing at it and only figure in gravity, then the horizontal component of velocity is constant, from the time the stone leaves your hand until the time it hits the ground. Makes no difference whether you toss it up, down, horizontal, or on a slant. Also makes no difference whether it's a cannonball, a stone, or a bullet.
An angle of 43 degrees cannot be a vertical angle. A vertical angle, by definition, is 90 degrees