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Where A Particle Is Projected Along A Linear Plane. The Horizontal Component Of The Velocity Is Twice The Vertical Component What Is The Initial Magnitude Of The Velocity And The Angle At Which It Is?
The initial magnitude of the velocity is sqrt(5) times the horizontal component. This results in a velocity vector that is inclined at an angle of arctan(2) ≈ 63.43 degrees with respect to the horizontal.
A golfer tees off and hits a golf ball at a speed of 31 ms and at an angle of 35 degrees. What is the vertical velocity component of the ball Round the answer to the nearest tenth of a ms.?
The vertical velocity component of the ball can be found by multiplying the initial speed (31 m/s) by the sine of the launch angle (35 degrees). Vertical velocity = 31 m/s * sin(35) ≈ 17.7 m/s. The vertical velocity component is approximately 17.7 m/s.
How does angle of projection affect the maximum height?
The angle of projection affects the maximum height by determining the vertical and horizontal components of the initial velocity. At 90 degrees (vertical), all the initial velocity is vertical which results in maximum height. As the angle decreases from 90 degrees, the vertical component decreases, leading to a lower maximum height.
A player kicks a soccer ball from ground level and sends it flying at an angle of 30 degrees?
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Why does 45 degrees give maximum range?
When an object is launched at a 45-degree angle, it splits the initial velocity into horizontal and vertical components equally. This allows for the maximum range because the horizontal component remains constant throughout the flight, while the vertical component decreases due to gravity. This balance between horizontal and vertical components at 45 degrees results in the maximum distance traveled before hitting the ground.
Where A Particle Is Projected Along A Linear Plane. The Horizontal Component Of The Velocity Is Twice The Vertical Component What Is The Initial Magnitude Of The Velocity And The Angle At Which It Is?
The initial magnitude of the velocity is sqrt(5) times the horizontal component. This results in a velocity vector that is inclined at an angle of arctan(2) ≈ 63.43 degrees with respect to the horizontal.
A golfer tees off and hits a golf ball at a speed of 31 ms and at an angle of 35 degrees. What is the vertical velocity component of the ball Round the answer to the nearest tenth of a ms.?
The vertical velocity component of the ball can be found by multiplying the initial speed (31 m/s) by the sine of the launch angle (35 degrees). Vertical velocity = 31 m/s * sin(35) ≈ 17.7 m/s. The vertical velocity component is approximately 17.7 m/s.
How does angle of projection affect the maximum height?
The angle of projection affects the maximum height by determining the vertical and horizontal components of the initial velocity. At 90 degrees (vertical), all the initial velocity is vertical which results in maximum height. As the angle decreases from 90 degrees, the vertical component decreases, leading to a lower maximum height.
What is the horizontal velocity of 25 degrees?
Multiply the speed by the cosine of the angle (25 degrees in this case). For the vertical velocity, multiply by the sine of 25 degrees.Multiply the speed by the cosine of the angle (25 degrees in this case). For the vertical velocity, multiply by the sine of 25 degrees.Multiply the speed by the cosine of the angle (25 degrees in this case). For the vertical velocity, multiply by the sine of 25 degrees.Multiply the speed by the cosine of the angle (25 degrees in this case). For the vertical velocity, multiply by the sine of 25 degrees.
A player kicks a soccer ball from ground level and sends it flying at an angle of 30 degrees?
13
Why does 45 degrees give maximum range?
When an object is launched at a 45-degree angle, it splits the initial velocity into horizontal and vertical components equally. This allows for the maximum range because the horizontal component remains constant throughout the flight, while the vertical component decreases due to gravity. This balance between horizontal and vertical components at 45 degrees results in the maximum distance traveled before hitting the ground.
What is the vertical velocity at the top of the path of a projecticle thrown striaght up or launched at an angle?
The vertical velocity at the top of the path of a projectile thrown straight up is 0 m/s because it momentarily stops before falling back down. For a projectile launched at an angle, the vertical velocity at the top of the path depends on the initial velocity and launch angle, but it will also momentarily be 0 m/s before changing direction.
What is A boat moves at an angle of 60 in a horizontal line The x component of the boats velocity is 5 m s What is its y component of velocity?
You have a right triangle and can use trig. Degree mode. tan(theta) = adjacent/opposite( y component ) tan( 60 degrees) = (5 m/s)/(y comp.) y component = 5 m/s)/(tan 60 degrees) = 2.887 m/s ( you can call it 3 m/s ) -----------------------------------------------
If a basketball player throws a ball from 2.0m in the air towards the hoop 10m away If the hoop is 3.05m off the ground and the initial angle is 40 degrees what is the initial velocity?
The initial velocity of the ball can be calculated using the kinematic equation for projectile motion. By using the vertical component of velocity (V0y) and the time of flight, we can determine the initial velocity needed for the ball to reach the hoop. The velocity components are V0x = V0 * cos(θ) and V0y = V0 * sin(θ), where θ is the initial angle. The time of flight in this case is determined by the vertical motion of the ball, and it can be found by using the equation of motion for the vertical direction, considering the initial vertical velocity, the gravitational acceleration, and the vertical displacement of the ball. Once these values are calculated, the initial velocity can be computed by combining the horizontal and vertical components of the motion.
A rock is thrown upward at an angle of 50 degree with respect to the horizontal As it risesm its horizontal component of velocity?
If you ignore the effect of the air grabbing at it and only figure in gravity, then the horizontal component of velocity is constant, from the time the stone leaves your hand until the time it hits the ground. Makes no difference whether you toss it up, down, horizontal, or on a slant. Also makes no difference whether it's a cannonball, a stone, or a bullet.
In projectile motion What Angle would horizontal and vertical distance be equal?
Can't say. It depends on the release velocity (muzzle velocity).The maximum horizontal distance always results from an angle of 45 degrees, regardless of the release velocity.
A golfer tees off and hits a golf ball at a speed of 31 ms and at an angle of 35 degrees. What is the horizontal velocity component of the ball Round the answer to the nearest tenth of a ms.?
The horizontal velocity component of the ball can be calculated using the formula: horizontal velocity = initial velocity * cos(angle). Substituting the values, we get: horizontal velocity = 31 m/s * cos(35 degrees) ≈ 25.3 m/s.
