0.67 atmospheres
B. 10 Cubic inches The formula is: po - original gas pressure vo - original volume pf - final gas pressure vf - final volume Po*Vo = Pf*Vf or 5psi x 20 in3 = 10psi x Vf
To convert between absolute pressure in kPa to gauge pressure in mm Hg, you can use the conversion factor of 1 kPa = 7.5 mm Hg. Therefore, if the required absolute pressure is 20 kPa, the corresponding gauge pressure would be 20 kPa * 7.5 mm Hg/kPa = 150 mm Hg.
During a tornado, the air pressure can drop significantly. It is not uncommon to see pressure drops of 10-20% below normal levels, which can correspond to pressures around 28 to 30 inches of mercury (950-1010 millibars).
There are 46.15 inches of water in a 20 psi pressure. This can be calculated using the formula: 1 psi = 2.307 feet of water, which is approximately 27.69 inches. 20 psi x 27.69 inches/psi = 46.15 inches.
Usually we use a temperature of 20 °C and an absolute pressure of 101.325 kPa for 1 atmosphere.
To find the absolute pressure in the piping system, you can convert the vacuum gauge reading to absolute pressure using the barometric pressure. The absolute pressure (P_abs) can be calculated as follows: P_abs = P_atm - P_vacuum = 30.71 inches of mercury - 20 inches of mercury = 10.71 inches of mercury. Thus, the absolute pressure in the piping system is 10.71 inches of mercury.
To calculate the absolute pressure, first convert the vacuum gauge reading to pressure in inches of mercury (inHg). Since the vacuum gauge reads 20 inches, the absolute pressure is the barometric pressure minus the vacuum gauge reading: (30.71 , \text{inHg} - 20 , \text{inHg} = 10.71 , \text{inHg}). Therefore, the absolute pressure is 10.71 inches of mercury.
10 cubic inches
twenty inches of mercury
B. 10 Cubic inches The formula is: po - original gas pressure vo - original volume pf - final gas pressure vf - final volume Po*Vo = Pf*Vf or 5psi x 20 in3 = 10psi x Vf
To convert between absolute pressure in kPa to gauge pressure in mm Hg, you can use the conversion factor of 1 kPa = 7.5 mm Hg. Therefore, if the required absolute pressure is 20 kPa, the corresponding gauge pressure would be 20 kPa * 7.5 mm Hg/kPa = 150 mm Hg.
During a tornado, the air pressure can drop significantly. It is not uncommon to see pressure drops of 10-20% below normal levels, which can correspond to pressures around 28 to 30 inches of mercury (950-1010 millibars).
Usually we use a temperature of 20°C and an absolute pressure of 101.325 kPa for 1 atmospher.
At standard temperature and pressure, there aren't 20 liquid elements. The only one would be mercury and bromine. If you change the temperature and pressure appropriately, any of the elements could conceivable be a liquid.
There are 46.15 inches of water in a 20 psi pressure. This can be calculated using the formula: 1 psi = 2.307 feet of water, which is approximately 27.69 inches. 20 psi x 27.69 inches/psi = 46.15 inches.
The absolute pressure at 20 meters underwater can be calculated using the formula: ( P = P_{atm} + \rho g h ), where ( P_{atm} ) is the atmospheric pressure at sea level (approximately 101.3 kPa), ( \rho ) is the density of water (around 1000 kg/m³), ( g ) is the acceleration due to gravity (approximately 9.81 m/s²), and ( h ) is the depth in meters. At 20 meters, the pressure due to the water column is about 196.2 kPa (1000 kg/m³ × 9.81 m/s² × 20 m). Adding atmospheric pressure, the total absolute pressure is approximately 297.5 kPa.
There are a few ways to define "opposite." It could be -20 or 1/20. The absolute value of 20 is 20.