Yes. Gravity is a fundamental force that is the attraction between any object. It has nothing to do with pressure or gases.
Note that while some people may explain that it acts between two masses, and while this is true, it also affects light particles which have no mass.
Currently gravity is described as an effect on the space-time-continuum. Just imagine a heavy ball on a trampoline, but in 3D space rather than the 2D surface of the trampoline. A body with mass will create a sort of 'dip' in space which an object will fall into, including light.
are you talking about sub atomic particles ? and do you agree that outer space is a vacuum ?
and so what holds us to earth ? Earth has it's own atmosphere and the pressure inside that atmosphere is what holds us to Earth ! It is not magnetism !
Now as we venture into space , we ask what are "Black holes"
To understand this , we must think of outer space, as Flat !!
Then we can bigin to understand the Paradox of "Black Holes"
Jon R. Stefanik SR.
No, changing the mass of a free-falling body does not affect the value of the acceleration due to gravity. The acceleration due to gravity is a constant value that is independent of the mass of the object. All objects fall at the same rate in a vacuum due to gravity.
The acceleration due to Gravity is constant at 32 feet per second per second, if you dropped a feather and a cannon ball in a vacuum they would fall at the same rate and hit the floor at he same time.
acceleration due to gravity of earth is 9.8ms-2
I suppose you are asking about what forces change when acceleration due to gravity changes. In this case, the formula for forces concerning acceleration due to gravity is as such: fg=mg. When acceleration due to gravity(g) changes, it affects the force of gravity which is also known as the weight of the object. This is shown as fg.
In a vacuum, air resistance is eliminated, and all objects fall due to gravity alone. The acceleration due to gravity is the same for all objects regardless of their mass, so they fall at the same speed in a vacuum.
If you mean acceleration due to gravity it is ~9.8m/s2
Unless you drop the feather in a vacuum, air resistance will be significant, so any acceleration (change in velocity) will not be due solely to gravity.
No, changing the mass of a free-falling body does not affect the value of the acceleration due to gravity. The acceleration due to gravity is a constant value that is independent of the mass of the object. All objects fall at the same rate in a vacuum due to gravity.
The acceleration due to Gravity is constant at 32 feet per second per second, if you dropped a feather and a cannon ball in a vacuum they would fall at the same rate and hit the floor at he same time.
acceleration due to gravity of earth is 9.8ms-2
Acceleration due to gravity on Saturn = 11.171 m/s2 (9.807 m/s2 on Earth)
I suppose you are asking about what forces change when acceleration due to gravity changes. In this case, the formula for forces concerning acceleration due to gravity is as such: fg=mg. When acceleration due to gravity(g) changes, it affects the force of gravity which is also known as the weight of the object. This is shown as fg.
In a vacuum, air resistance is eliminated, and all objects fall due to gravity alone. The acceleration due to gravity is the same for all objects regardless of their mass, so they fall at the same speed in a vacuum.
No, acceleration due to gravity does not change the weight of an object. Weight is determined by the mass of the object and the acceleration due to gravity in that location. The acceleration due to gravity affects the force with which an object is pulled toward the center of the Earth, leading to its weight.
Acceleration due to gravityThe acceleration produced in the motion of a body under gravity is called Acceleration.
In a vacuum, both the leaf and the stone would fall with the same acceleration, as they would be subject only to the force of gravity. This is because the acceleration due to gravity is constant regardless of an object's mass.
The period of a pendulum (in seconds) is 2(pi)√(L/g), where L is the length and g is the acceleration due to gravity. As acceleration due to gravity increases, the period decreases, so the smaller the acceleration due to gravity, the longer the period of the pendulum.